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Calculate the Fermi energy for noninteracting electrons in a two-dimensional infinite square well. Let 蟽 be the number of free electrons per unit area.

Short Answer

Expert verified

The Fermi energy for electrons in a two-dimensional infinite square well is

EF=h2m

Step by step solution

01

Definition of Fermi energy of electron

The greatest energy that an electron may hold at 0K is known as the Fermi energy.

Equation 5.50

Enxny=2h22mnx2lx2+ny2ly2=h2k22m,withk=nxlx,nyly

02

Calculating the Fermi energy for electrons in a two-dimensional infinite square well

Each state is represented by an intersection on a grid in k-space鈥-this time a plane-and each state occupies an area 2/lxly=2/A( whereAlxly is the area of the well). Two electrons per state means

Enxnynz=h22mnx2lx2+ny2ly2+nz2lz2=h2k22m 鈥(5.50).

14k2=Nq22A,orkF=2NqA1/2=21/2

where Nq/Ais the number of free electrons per unit area.

EF=h2kF22m=h22m2=h2m

Thus the Fermi energy for electrons in a two-dimensional infinite square well is

EF=h2m

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Most popular questions from this chapter

(a) Figure out the electron configurations (in the notation of Equation

5.33) for the first two rows of the Periodic Table (up to neon), and check your

results against Table 5.1.

1s22s22p2(5.33).

(b) Figure out the corresponding total angular momenta, in the notation of

Equation 5.34, for the first four elements. List all the possibilities for boron,

carbon, and nitrogen.

LJ2S+1 (5.34).

Suppose you could find a solution(r1,r2,...,rz)to the Schr枚dinger equation (Equation 5.25), for the Hamiltonian in Equation 5.24. Describe how you would construct from it a completely symmetric function, and a completely anti symmetric function, which also satisfy the Schr枚dinger equation, with the same energy.

role="math" localid="1658219144812" H^=j=1Z-22mj2-14o,0Ze2rj+1214o,0j1Ze2rj-rk (5.24).

role="math" localid="1658219153183" H^=E (5.25).

Discuss (qualitatively) the energy level scheme for helium if (a) electrons were identical bosons, and (b) if electrons were distinguishable particles (but with the same mass and charge). Pretend these 鈥渆lectrons鈥 still have spin 1/2, so the spin configurations are the singlet and the triplet.

Suppose you had three particles, one in statea(x), one in stateb(x), and one in statec(x). Assuming a,b, andc are orthonormal, construct the three-particle states (analogous to Equations 5.15,5.16, and 5.17) representing

(a) distinguishable particles,

(b) identical bosons, and

(c) identical fermions.

Keep in mind that (b) must be completely symmetric, under interchange of any pair of particles, and (c) must be completely antisymmetric, in the same sense. Comment: There's a cute trick for constructing completely antisymmetric wave functions: Form the Slater determinant, whose first row isa(x1),b(x1),c(x1) , etc., whese second row isa(x2),b(x2),c(x2) , etc., and so on (this device works for any number of particles).

Derive the Stefan-Boltzmann formula for the total energy density in blackbody radiation

EV=(2kB4153C3)T4=7.5710-16Jm-3K-4T4

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