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Suppose you had three particles, one in statea(x), one in stateb(x), and one in statec(x). Assuming a,b, andc are orthonormal, construct the three-particle states (analogous to Equations 5.15,5.16, and 5.17) representing

(a) distinguishable particles,

(b) identical bosons, and

(c) identical fermions.

Keep in mind that (b) must be completely symmetric, under interchange of any pair of particles, and (c) must be completely antisymmetric, in the same sense. Comment: There's a cute trick for constructing completely antisymmetric wave functions: Form the Slater determinant, whose first row isa(x1),b(x1),c(x1) , etc., whese second row isa(x2),b(x2),c(x2) , etc., and so on (this device works for any number of particles).

Short Answer

Expert verified

a) The distinguishable particles: x1,x2,x3颈蝉蠄ax1bx2cx3

b) The identical bosons

1,2,3,-16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3+16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3

c) The identical fermions

1,2,3,-16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3+16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3

Step by step solution

01

Definition of identical bosons ,identical ferminos and slater determinant

  • "Particles come in two types: the particles that make up matter, known as 'fermions,' and the particles that transport forces, known as 'bosons,' according to Carroll.
  • Fermions take up space, whereas bosons can be stacked on top of one another.
  • A Slater determinant is a formula in quantum mechanics that describes the wave function of a multi-fermionic system.
  • It satisfies anti-symmetry criteria, and thus the Pauli principle, by changing sign when two electrons are exchanged (or other fermions)

02

Determine the Slater determinant

WhenNfermionsarepresent,thewholewavefunctioncanberepresentedas:x2,...,xN)=1N!ax1bx1...Nx1ax1bx1...Nx2...axNbxN...NxNTheSlaterdeterminantisthenameforthisformula.

03

Determine the distinguishable particles

(a)

The total wave function for identifiable particles is simply the combination of three wave functions:

x1,x2,x3=ax1bx2cx3

04

Determine the  identical bosons

(b)

When we permute any two particles, the entire wave function for identical bosons must be symmetric:

x1,x2,x3,-16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3+16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3

05

Determine the  identical fermions

(c)

When we permute any two fermions, the whole wave function must be antisymmetric for identical fermions:

x1,x2,x3,-16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3+16ax1bx2cx3+ax1bx2cx3+ax1bx2cx3

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Most popular questions from this chapter

(a)Use Equation5.113 to determine the energy density in the wavelength ranged. Hint: set()d蝇=-()诲位, and solve for()-

(b)Derive the Wien displacement law for the wavelength at which the blackbody energy density is a maximum
max=2.9010-3mKT

You'll need to solve the transcendental equation(5x)=5e-x, using a calculator (or a computer); get the numerical answer accurate to three significant digits.

Find the energy at the bottom of the first allowed band, for the case=10 , correct to three significant digits. For the sake of argument, assume a=1eV.

(a) Suppose you put both electrons in a helium atom into the n=2state;

what would the energy of the emitted electron be?

(b) Describe (quantitatively) the spectrum of the helium ion,He+.

(a) If aandb are orthogonal, and both normalized, what is the constant A in Equation 5.10?

(b) Ifrole="math" localid="1658225858808" a=b (and it is normalized), what is A ? (This case, of course, occurs only for bosons.)

The density of copper is8.96g/cm3,and its atomic weight is63.5g/mole

(a) Calculate the Fermi energy for copper (Equation 5.43). Assume d = 1, and give your answer in electron volts.

EF=22m3蚁蟺22/3 (5.43).

(b) What is the corresponding electron velocity? Hint: SetEF=1/2mv2Is it safe to assume the electrons in copper are nonrelativistic?

(c) At what temperature would the characteristic thermal energyrole="math" localid="1656065555994" (kBT,wherekBkBis the Boltzmann constant and T is the Kelvin temperature) equal the Fermi energy, for copper? Comment: This is called the Fermi temperature,TF

. As long as the actual temperature is substantially below the Fermi temperature, the material can be regarded as 鈥渃old,鈥 with most of the electrons in the lowest accessible state. Since the melting point of copper is 1356 K, solid copper is always cold.

(d) Calculate the degeneracy pressure (Equation 5.46) of copper, in the electron gas model.

P=23EtotV=232kF5102m=322/325m5/3

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