/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10P Discuss (qualitatively) the ener... [FREE SOLUTION] | 91影视

91影视

Discuss (qualitatively) the energy level scheme for helium if (a) electrons were identical bosons, and (b) if electrons were distinguishable particles (but with the same mass and charge). Pretend these 鈥渆lectrons鈥 still have spin 1/2, so the spin configurations are the singlet and the triplet.

Short Answer

Expert verified

(a)The ground state (Eq. 5.30) is spatially symmetric, so it goes with the symmetric (triplet) spin configuration.

(b) The ground state (Eq. 5.30) and all excited states (Eq. 5.32) come in both ortho and para form.

Step by step solution

01

(a) If electrons were identical bosons

The ground state (Equation 5.30) fits into a symmetric (triplet) spin configuration because it is spatially symmetric.

Thus, orthohelium, a degenerate triple, is the ground state. Ortho (triplet) and para excited states (Equation 5.32) are two types of excited states (singlet). The energy level of the orthohelium state is higher than that of the comparable (non-degenerate) para-state since the former is linked to the symmetric space wavefunction.

0r1,r2=100r1100r2=8a3e-2r1+r2/a 鈥(5.30)

nm100 ...(5.32).

02

(b) Spinning the configurations are the singlet and the triplet

Both orthogonal and paragon variants of the ground state (Eq. 5.30) and all stimulated states (Eq. Everything is degenerate four times, or alternatively, we don't know what happens in a symmetric spatial composition, so we can't determine which is more energetic鈥攁t least ortho or para.

0r1,r2=100r1100r2=8a3e-2r1+r2/a 鈥(5.30).

nm100 ...(5.32).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Figure out the electron configurations (in the notation of Equation

5.33) for the first two rows of the Periodic Table (up to neon), and check your

results against Table 5.1.

1s22s22p2(5.33).

(b) Figure out the corresponding total angular momenta, in the notation of

Equation 5.34, for the first four elements. List all the possibilities for boron,

carbon, and nitrogen.

LJ2S+1 (5.34).

(a) If aandb are orthogonal, and both normalized, what is the constant A in Equation 5.10?

(b) Ifrole="math" localid="1658225858808" a=b (and it is normalized), what is A ? (This case, of course, occurs only for bosons.)

Certain cold stars (called white dwarfs) are stabilized against gravitational collapse by the degeneracy pressure of their electrons (Equation 5.57). Assuming constant density, the radius R of such an object can be calculated as follows:

P=23EtotV=23h2kF5102m=(32)2/3h25mp5/3(5.57)

(a) Write the total electron energy (Equation 5.56) in terms of the radius, the number of nucleons (protons and neutrons) N, the number of electrons per nucleon d, and the mass of the electron m. Beware: In this problem we are recycling the letters N and d for a slightly different purpose than in the text.

Etot=h2V22m0kFK4dk=h2kF5V102m=h2(32Nd)5/3102mV-2/3(5.56)

(b) Look up, or calculate, the gravitational energy of a uniformly dense sphere. Express your answer in terms of G (the constant of universal gravitation), R, N, and M (the mass of a nucleon). Note that the gravitational energy is negative.

(c) Find the radius for which the total energy, (a) plus (b), is a minimum.

R=(94)2/3h2d5/3GmM2N1/3

(Note that the radius decreases as the total mass increases!) Put in the actual numbers, for everything except , using d=1/2 (actually, decreases a bit as the atomic number increases, but this is close enough for our purposes). Answer:

(d) Determine the radius, in kilometers, of a white dwarf with the mass of the sun.

(e) Determine the Fermi energy, in electron volts, for the white dwarf in (d), and compare it with the rest energy of an electron. Note that this system is getting dangerously relativistic (seeProblem 5.36).

Show that most of the energies determined by Equation 5.64are doubly degenerate. What are the exceptional cases? Hint: Try it for N=1,2,3,4.... , to see how it goes. What are the possible values of cos(ka)in each case?

(a) Using Equations 5.59 and 5.63, show that the wave function for a particle in the periodic delta-function potential can be written in the form

(X)=C[sinkx+e-ikasina-x]0xa

(b) There is an exception; At the top of a band where z is an integer multiple ofyiels(x)=0 yields .

Find the correct wave function for the case. Note what happens toeach delta function.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.