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Show that most of the energies determined by Equation 5.64are doubly degenerate. What are the exceptional cases? Hint: Try it for N=1,2,3,4.... , to see how it goes. What are the possible values of cos(ka)in each case?

Short Answer

Expert verified

There is no degeneracy at the top and the bottom of the band whencoska=1

Step by step solution

01

Define the Schrodinger equation

  • A differential equation for the quantum mechanical description of matter in terms of the wave-like characteristics of particles in a field. The solution has to do with the probability density of a particle in space and time.
  • The time-dependent Schrodinger equation is represented as

颈魔ddt(t)>=H(t)>

02

Analyze the condition

For Ka=2蟺苍/Nwe have a condition on n:n=0,12,...,N-1. Because for larger n, we don't get new solutions.

We are going to write solutions for cosKafor couple of N

Ka=2蟺苍N

Value of different ncorresponds to a distinct state

03

Analyze the energies

N=1,n=0coska=1Non- degenerate

N=2,n=0,1coska=1,1Non- degenerate

N=3,n=0,1,2cos(ka)=1,-12,-12First one is non -degenerate other one is degenerate

N=4,n=0,1,2,3cos(ka)=1,0,-1,0Two are non -degenerate and two are degenerate

When we have coska=1, then we don't have degeneracy. This happens at the top and at the bottom of the band.

So, we don鈥檛 have degeneracy at the top and the bottom of the band whencos(ka)=1

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