/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q48P One of the harmonic frequencies ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

One of the harmonic frequencies of tube Awith two open ends is 325Hz. The next-highest harmonic frequency is 390Hz. (a) What harmonic frequency is next highest after the harmonic frequency 195Hz? (b) What is the number of this next-highest harmonic? One of the harmonic frequencies of tube Bwith only one open end is 1080Hz. The next-highest harmonic frequency is 1320Hz. (c) What harmonic frequency is next highest after the harmonic frequency 600Hz? (d) What is the number of this next-highest harmonic?

Short Answer

Expert verified
  1. The harmonic frequency next highest after the harmonic frequency 195Hz is 260Hz.
  2. The number of this next highest harmonics is 4.
  3. The harmonic frequency next highest after the harmonic frequency 600Hz is 840Hz.
  4. The number of this next highest harmonics is 7.

Step by step solution

01

Identification of given data

  1. One of the harmonic frequencies of A, (fa1) = 325Hz.
  2. The next highest frequency of A, (fa2) = 390Hz
  3. One of the frequencies of B, (fb1) = 1080Hz
  4. The next highest frequency of B, (fb2) = 1320Hz
  5. One of the frequencies of A, (fa1) = 195Hz
  6. One of the frequencies of B, (fb1) = 600Hz
02

Significance of frequency

The number of waves passing a fixed location in a unit of time is referred to as frequency in physics.

We can find the fundamental frequency from two given successive frequencies for a pipe open at both ends. Using it, we can easily find the harmonic frequency next highest after the harmonic frequency 195 Hz. The ratio of the given frequency with the first harmonic frequency will give several modes. Similarly, we can answer parts c) and d) using formulae for pipe closed at one end.

Formula:

For a pipe open at both ends,

  1. f = fn - fn-1
  2. The number of harmonics, fn / f
  3. For pipe open at one end,f=fn-fn-12
03

(a) Determining the harmonic frequency

Using equation (i) from the formula, the first harmonic frequency of A for both ends open is given as:

fa=fa2-fa1

Therefore, the first harmonic frequency of A is given as:

fa=fa2-fa1

The next highest frequency after 195 Hz is: 195Hz+65Hz = 260Hz

Hence, the value of the harmonic frequency is 260Hz.

04

(b) Determining the number of higher harmonics

The number of harmonic frequencies of A is given using formula (ii) as follows:

NA=260Hz65Hz=4

Hence, the number of harmonic frequencies is 4.

05

(c) Determining the harmonic frequency of B

Using equation (iii) from the formula, the first harmonic frequency of B for one end open is given as:fb=fb2-fb1/2

The first harmonic frequency of B:

fb=121320Hz-1080Hz=240Hz2=120Hz

The next highest frequency after 600Hz is given as:

fb2'=fb2'+fb=600Hz+2×120Hz=840Hz

Hence, the value of the harmonic frequency is 840Hz.

06

d) Determining the number of harmonics of B

The number of harmonic frequencies of B is given using formula (ii) as follows:

NB=840Hz120Hz=7

Hence, the number of harmonics is 7.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are standing at a distance D from an isotropic point source of sound. You walk50.0m toward the source and observe that the intensity of the sound has doubled. Calculate the distanceD.

In Fig. 17-25, two point sources S1andS2, which are in phase, emitidentical sound waves of wavelength2.0m. In terms of wavelengths, what is the phase differencebetween the waves arriving atpoint Pif (a)L1=38mandL2=34m, and (b)L1=39mandL2=36m? (c) Assuming that the source separation is much smaller thanL1andL2, what type of interference occurs atin situations (a) and (b)?

The sixth harmonic is set up in a pipe. (a) How many open ends does the pipe have (it has at least one)? (b) Is there a node, antinode, or some intermediate state at the midpoint?

Figure shows two isotropic point sources of sound S1 and S2The sources emit waves in phase at wavelength 0.50m; they are separated byD=1.75m . If we move a sound detector along a large circle centered at the midpoint between the sources, at how many points do waves arrive at the detector(a) Exactly in phase and (b) Exactly out of phase ?

Question: In Fig. 17-27, pipe Ais made to oscillate in its third harmonicby a small internal sound source. Sound emitted at the right endhappens to resonate four nearby pipes, each with only one openend (they are notdrawn to scale). Pipe Boscillates in its lowestharmonic, pipe Cin its second lowest harmonic, pipe Din itsthird lowest harmonic, and pipe Ein its fourth lowest harmonic.Without computation, rank all five pipes according to theirlength, greatest first. (Hint:Draw the standing waves to scale andthen draw the pipes to scale.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.