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Find the ratios (greater to smaller) of the (a) intensities, (b) pressure amplitudes, and (c) particle displacement amplitudes for two sounds whose sound levels differ by 37鈥塪叠.

Short Answer

Expert verified
  1. Ratio of intensities is,5000 .
  2. Ratio of pressure amplitude is, 71.
  3. Ratio of particle displacement amplitudes is, 71.

Step by step solution

01

The given data

Sound levels differ by =37鈥塪产.

02

Understanding the concept of sound intensity and pressure

We have to use the formula for sound level in terms of intensity to calculate the intensity ratio. To calculate the ratio of pressure amplitudes, we will use the formula for pressure amplitude in terms of displacement amplitude.

Formula:

The scale of sound intensity level,

螖尾=(10鈥塪叠)log(I1I2) 鈥(颈)

The ratio of pressure amplitudes,

螖辫m1螖辫m2=I1I2 鈥(颈颈)

The ratio of displacement amplitude,

sm1sm2=I1I2 鈥(颈颈颈)

03

a) Calculation of ratio of intensities 

We are given the difference in sound levels. We can find intensity ratio by taking antilog on both sides of equation (i) as:

I1I2=10螖尾/10鈥塪叠=1037鈥塪叠10鈥塪叠=103.7=5011.872I1I25012

Hence, the value of ratio of intensities is 5012.

04

b) Calculation of ratio of pressure amplitude

Using equation (ii), and the value of intensity ratio, we get the ratio of pressure amplitude as:

螖辫m1螖辫m2=I1I2=5011.87=70.79螖辫m1螖辫m2=71

Hence, the value of ratio of pressure amplitude is71 .

05

c) Calculation of ratio of displacement amplitude

Using equation (iii) and the value of intensity ratio, we can get the displacement amplitude as:

sm1sm2=I1I2=5011.87=70.79sm1sm271

Hence, the value of ratio of displacement amplitude is71 .

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