/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7Q Question: Figure 17-28 shows a m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: Figure 17-28 shows a moving sound source S that emits at a certain

frequency, and four stationary sound detectors. Rank the detectors

according to the frequency of the sound they detect from the

source, greatest first.

Short Answer

Expert verified

Answer

The rank of detectors, according to the frequency of sound they detect, greatest first is detector 1, detector 4, detector 3, and detector 2.

Step by step solution

01

Step 1: Stating given data

  1. S is the moving source of sound.
  2. 1, 2, 3 and 4 are stationary detectors.
02

Determining the concept

In the given situation, the sound of the source is moving while the four detectors are stationary. Hence, the Doppler Effect is observed here. The frequency of the source changes apparently for each detector, depending on its position relative to the moving source.

The formula is as follows:

f'=fv±vDv±vs

where f is the frequency and vis the velocity.

03

Determining the rank of detectors according to the frequency of sound they detect, greatest first

The general equation ofthedoppler effect is

f'=fv±vDv±vs

The signs are chosen such that f increases when the motion is towards, and decreases when the motion is away from, the source.

In the given diagram, source S is moving towards detector 1. Hence, the observed frequency by detector 1 will be greater than f. In fact, it will be greatest among the frequencies detected bytheother three detectors.

For detector 4, the source is moving towards it, though along a different line. Hence, it will also observe the frequency ´Ú’ greater than f. But as detector 4 is not along the line, the increase will be less than that for detector 1.

For detector 3, the instantaneous position of the source S is at the same point, though along a different line. Hence, for detector 3, the observed frequency is the same as the actual frequency .

For detector 2, the source S is moving away from it. Hence, the observed frequency f will be lesser than frequency . Thus, the ranking of the detectors will be detector 1, detector 4, detector 3, and detector 2.

Therefore, the Doppler Effect is observed when there is relative motion between the source of the sound and the detector. As the source moves towards the detector, the observed frequency increases. If the source moves away from the detector, the observed frequency decreases compared to the actual frequency. This observation can be used to determine the ranking of the detectors.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A bullet is fired with a speed of 685″¾/s . Find the angle made by the shock cone with the line of motion of the bullet.

Question: A man strike one end of a thin rod with a hammer. The speed of sound in the rod is 15times the speed of sound in the air. A woman, at the other end with her ear close to the rod, hears the sound of the blow twice with a 0.12 sinterval between; one sound comes through the rod and the other comes through the air alongside the rod. If the speed of sound in air is 343 m/swhat is the length of the rod?

A violin string 30.0cmlong with linear density 0.650g/mis placed near a loudspeaker that is fed by an audio oscillator of variable frequency. It is found that the string is set into oscillation only at the frequencies 880Hzand 1320Hzas the frequency of the oscillator is varied over the range 500-1500Hz. What is the tension in the string?

Two identical tuning forks can oscillate at 440 H³ú. A person is located somewhere on the line between them. Calculate the beat frequency as measured by this individual if (a) she is standing still and the tuning forks move in the same direction along the line at,3.00″¾/s (b) the tuning forks are stationary and the listener moves along the line at 3.00″¾/s.

A certain loudspeaker system emits sound isotropically with a frequency of 2000 H³ú and an intensity ofrole="math" localid="1661500478873" 0.960″¾W/m2 at a distance ofrole="math" localid="1661501289787" 6.10″¾ . Assume that there are no reflections. (a) What is the intensity at 30.0″¾? At 6.10″¾, what are (b) the displacement amplitude and (c) the pressure amplitude?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.