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Chapter 37: Q91P (page 1151)

In Fig. 37-36, two cruisers fly toward a space station. Relative to the station, cruiser A has speed 0.800c. Relative to the station, what speed is required of cruiser B such that its pilot sees A and the station approach B at the same speed?

Short Answer

Expert verified

The speed of cruiser B such that cruiser A and station approaches it with same speed is 0.400c.

Step by step solution

01

Identification of given data

The relative speed of Cruiser A is vA=0.800c

The relative speed of cruiser A relative to B will be equal to the relative speed of cruiser B relative to station. The station is stationary so its speed will be zero relative to both cruisers.

02

Determination of speed of cruiser B

The speed of cruiser B is given as:

vs-vB=vB-vAvB=vs+vA2

Here, vs is the speed of station and its value is zero because both cruisers are at rest.

Substitute all the values in the above equation.

vB=0+0.800c2vB=0.400c

Therefore, the speed of cruiser B such that cruiser A and station approaches it with same speed is 0.400c.

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