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Calculate the probability that the electron in the hydrogen atom, in its ground state, will be found between spherical shells whose radii are a and 2a , where a is the Bohr radius?

Short Answer

Expert verified

The required probability is P=0.439.

Step by step solution

01

Identification of the given data:

The given data is listed below.

  • Radii of the spherical shells are given as a and 2a .
02

Formula for finding the probability of electron:

The ground state wave function of hydrogen atom is given by,

ψ100(r,θ,ϕ)=1π(1a)32e-ra

Here, the Bohr radius is a=5.292×10-11m.

03

Determine the probability of the electron in the hydrogen atom in its ground state:

The probability of finding the electron found between spherical shells is,

P=∫a2a∫0π∫02πψ100r,θ,Ï•2r2»å°ù²õ¾±²Ôθ»åθ»åÏ•=∫a2a1Ï€1a32e-ra2r2dr∫0Ï€»åÏ•=1Ï€1a3∫a2ae-ra2r2dr×-³¦´Ç²õθ0πθ02Ï€=1Ï€1a3-14ae-2raa2+2ar+2r2a2a×-³¦´Ç²õÏ€+cos02Ï€-0

P=1π1a3-a4e-22aaa2+2a2a+22a2-e-2aaa2+2a2+2a2×--1+12π=1π1a3-a4e-413a2-e-25a2×4π=41a3-a40.018313a2-0.13535a2P=4-140.018313-0.13535=-4140.2379-0.6765=0.439

Hence, the probability of the electron in the hydrogen atom in its ground state is 0.439.

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