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Light of wavelength 624 nm is incident perpendicularly on a soap film (n = 1.33) suspended in air. What are the (a) least and (b) second least thicknesses of the film for which the reflections from the film undergo fully constructive interference?

Short Answer

Expert verified

The least thickness is 117 nm, and the 2nd least thickness is 352 nm.

Step by step solution

01

Interference in thin films

Bright colors reflected from thin oil on water and soap bubbles are a consequence of light interference. Due to the constructive interference of light reflected from the front and back surfaces of the thin film, these bright colors can be seen. For a perpendicular incident beam, the maximum intensity of light from the thin film satisfies the condition:

2L=(m+12)λn2 â¶Ä‰â¶Ä‰m=0, 1, 2,...(Maxima—bright film in the air)

where λ is the wavelength of the light in air, L is its thickness, and n2 is the film’s refraction index.

02

Thickness of the soap film

The least and the 2nd least thickness are associated with m=0, 1the order of maximum intensity. The thickness corresponding to this order of maxima is

For m=0;

Lo=m+12λ2n2=0+12624 nm2(1.33)=117 nm

For m=1;

L1=m+12λ2n2=1+12624 nm2(1.33)=352 nm

Thus, the least thickness is 117 nm, and the 2nd least thickness is 352 nm.

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