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Two waves of the same frequency have amplitudes 1.00 and 2.00. They interfere at a point where their phase difference is 60.0°. What is the resultant amplitude?

Short Answer

Expert verified

The resultant amplitude of wave is 2.65 .

Step by step solution

01

Identification of given data

The amplitude of first wave is A1=1

The amplitude of second wave is A2=2

The phase difference for both waves is ϕ=60°

The amplitude of the resultant wave is equal to the vector sum of the amplitude of each wave.

02

Determination of resultant amplitude of wave

The resultant amplitude of wave is given as:

A=A12+A22+2A1A2cosϕ

Substitute all the values in equation.

A=12+22+212cos60°A=7A=2.65

Therefore, the resultant amplitude of wave is 2.65.

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Most popular questions from this chapter

In Fig. 35-44, a broad beam of light of wavelength 630 nm is incident at 90° on a thin, wedge-shaped film with index of refraction 1.50. Transmission gives 10 bright and 9 dark fringes along the film’s length. What is the left-to-right change in film thickness?

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Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as rayr3(the light does not reflect inside material 2) andr4(the light reflects twice inside material 2). The waves ofr3and r4interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n1,n2and n3the type of interference, the thin-layer thickness Lin nanometers, and the wavelength λin nanometers of the light as measured in air. Whereλis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

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