91影视

$$\begin{gathered} B={10}^{-10}\mathrm{T} \\ l=10\mathrm{light}鈥�\mathrm{years} \end{gathered}$$

First we convert one light year to meter per second, after that, by using the relationship between energy density and magnetic field we calculate the energy stored in the field.

Formula:

$u_B=\frac{B^2}{2{渭}_0}$

According to the formula of energy density which is energy per unit volume if we multiply the volume of cube than we get energy stored in that field.

So first find the volume of the cube.

$$\begin{gathered} 1\mathrm{light}鈥�\mathrm{years}=3脳{10}^8脳365脳24脳60脳60 \\ 1\mathrm{light}鈥�\mathrm{years}=9.5脳{10}^{15}\mathrm{m}/\mathrm{s} \end{gathered}$$

The edge of the cube in m/s is

$$\begin{gathered} l=10脳9.5脳{10}^{15} \\ l=9.5脳{10}^{16} \end{gathered}$$

So, the volume of the cube as

$$\begin{gathered} V=l^3 \\ V={\left(9.5脳{10}^{16}\right)}^3 \\ V=8.5脳{10}^{50} \end{gathered}$$

Now formula of energy density as
$$\begin{gathered} u_B=\frac{B^2}{2{渭}_0} \\ U=\frac{B^2}{2{渭}_0}V \end{gathered}$$

So, by substituting the value we can get,

$$\begin{gathered} U=u_B脳V \\ U=\frac{{\left({10}^{-10}\right)}^2}{2脳4\mathrm{蟺}脳{10}^{-7}}脳8.5脳{10}^{50} \\ U=\frac{{10}^{-20}}{2.5脳{10}^{-6}}脳8.5脳{10}^{50} \\ U=3脳{10}^{36}\mathrm{J} \end{gathered}$$

Hence energy stored is $3脳{10}^{36}\mathrm{J}$