91影视

1. Small loop area$a=2.00c{m}^2=2.00脳{10}^{-4}{\mathrm{m}}^2$
2. Large circular loop radius $R=1.00\mathrm{m}$
3. Current in large loop changed at constant rate from 200A to -200A in time t = 1.00s

The current is constantly changing with time. Determine the current at different time instances. For the circular loop, the magnetic field depends on the current and radius. The emf is related to the change in flux with time.

Faraday's law of electromagnetic inductionstates, Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced in it.

Formulae are as follow:

$$\begin{gathered} B=\frac{{渭}_{0}l}{2R} \\ 蔚=-\frac{d\mathbf{蠒}}{dt} \end{gathered}$$

Where,$\mathbf{蠒}$is magnetic flux, B is magnetic field, I is current, R is resistance, 饾渶 is emf, , 饾渿₀is permeability.

Current in the large loop changed at constant rate from 200A to -200A in time

t = 1.00s

$l=l_0\left(1-2t\right)$and $l_0=200A$
At role="math" localid="1661852445388" $t=0\mathrm{s},l=200\mathrm{A}$

At $t=0.500\mathrm{s},l=0.00\mathrm{A}$

At $t=1.00\mathrm{s},l=-200\mathrm{A}$

Hence,

At t = 0s,

$$\begin{gathered} B=\frac{{渭}_{0}l}{2R}=\frac{\left(4\mathrm{蟺}脳{10}^{-7}\right)200\mathrm{A}}{2\left(1.00m\right)} \\ B=1.26脳{10}^{-4}T \end{gathered}$$

Hence, the magnitude of the magnetic field at the center of the small loop due to the current in the large loop at t = 0S is $B=1.26脳{10}^{-4}T$.

At t = 0.500s,

B = 0.0T

Hence, the magnitude of the magnetic field at the center of the small loop due to the current in the large loop at t = 0.500s is B = 0.0T

At t = 1.00s,

$$\begin{gathered} B=\frac{{渭}_{0}l}{2R} \\ B=\frac{\left(4\mathrm{蟺}脳{10}^{-7}\right)\left(-200A\right)}{2\left(100m\right)} \\ B=-1.26脳{10}^{-4}T \end{gathered}$$

Hence, the magnitude of the magnetic field at the center of the small loop due to the current in the large loop at$t=1.00s$ is$B=-1.26脳{10}^{-4}T$

The current changed from 200A to -200A the magnetic field has reversed from $1.26脳{10}^{-4}$ T to$-1.26脳{10}^{-4}$T in time t = 0s to t = 1.00s.

Hence, the magnetic field is reversed.

The emf induced in a small loop is given by,

$蔚=\frac{d\mathbf{蠒}}{dt}$

Also, the flux can be written in terms of current and loop area,

$\mathrm{蠒}=\frac{{\mathrm{渭}}_0\mathrm{lA}}{2\mathrm{R}}$

Where, A is the area of the small loop i.e.a = 2.00$脳$${10}^{-4}{\mathrm{m}}^2$

role="math" localid="1661853987331" $$\begin{gathered} 蔚=-\frac{d\mathbf{蠒}}{dt} \\ 蔚=-\frac{d}{dt}\frac{{\mathrm{渭}}_0\mathrm{lA}}{2\mathrm{R}} \\ 蔚=-\frac{{\mathrm{渭}}_0\mathrm{lA}}{2\mathrm{R}}\frac{dl}{dt} \\ 蔚=\frac{\left(4\mathrm{蟺}脳{10}^{-7}\right)2.00脳{10}^{-4}{\mathrm{m}}^2\left(-200\mathrm{A}-\left(200\mathrm{A}\right)\right)}{2\left(1.00m\right)\left(1.00s\right)} \\ 蔚=5.04脳{10}^{-8}V \end{gathered}$$

Hence, the emf induced in the small loop at t = 0.500s is $蔚=5.04脳{10}^{-8}\mathrm{V}$.

Therefore, find the magnetic field for the circular loop at different time instances using the current at the given time and radius. The emf is determined with the change in flux.