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Figure 34-27 is an overhead view of a mirror maze based on floor sections that are equilateral triangles. Every wall within the maze is mirrored. If you stand at entrance x, (a) which of the maze monsters a, b, and chiding in the maze can you see along the virtual hallways extending from entrance x; (b) how many times does each visible monster appear in a hallway; and (c) what is at the far end of a hallway?

Short Answer

Expert verified

(a) The maze monstersa andc can be seen along the virtual hallways extending from the entrance.

(b) Each visible monster will appear 3 times in a hallway.

(c) You are at the far end of a hallway.

Step by step solution

01

Definition of reflection

The bouncing back of the ray of light after hitting a smooth platform is known as reflection. The ray that hits the surface is called an incident ray and the ray that bounces back is termed a reflected ray.

02

(a) Determination of the maze monsters that can be seen from virtual hallways

Show the multiple reflections of light rays from the given points in the figure.

From the above figure, it can be said that an observer can see monstersa andc along the virtual hallway extending from the entrance x. After analyzing the above figure, we can also note that the light rays from point b will reflect multiple times in the mirror maze and diminish and will not reach at x. This implies that, the observer can’t see monster b along the virtual hallway extending from the entrance x.

Thus, the light ray from pointa andc reaches atx after multiple reflections.

03

(b) Determination of what times the monster will appear

As each mirror is a part of equilateral triangle, three images of each visible monster will be produced.

Thus, the monster will appear three times bigger.

04

(c) Determination of the object that is at the far end of the hallway

Obtain the ray diagram follows,

From the above ray diagram, we can conclude that after multiple reflections from x, the virtual image of role="math" localid="1662993498688" x, that is x', will get formed at the far end of hallway and then, again undergoing multiple reflections through the maze, the light rays will reach to x.

Thus, this implies that, you can see yourself at the far end of a hallway.

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Most popular questions from this chapter

A man looks through a camera toward an image of a hummingbird in a plane mirror. The camera is 4.30m in front of the mirror. The bird is at the camera level, 5.00mto the man’s right and 3.30mfrom the mirror. What is the distance between the camera and the apparent position of the bird’s image in the mirror?

The formula 1p+1i=1f is called the Gaussian form of the thin-lens formula. Another form of this formula, the Newtonian form, is obtained by considering the distance xfrom the object to the first focal point and the distancex' from the second focal point to the image. Show thatxx'=f2 is the Newtonian form of the thin-lens formula

17 through 29 22 23, 29 More mirrors. Object O stands on the central axis of a spherical or plane mirror. For this situation, each problem in Table 34-4 refers to (a) the type of mirror, (b) the focal distancef, (c) the radius of curvaturer, (d) the object distancep, (e) the image distancei, and (f) the lateral magnification localid="1663002056640" m. (All distances are in centimeters.) It also refers to whether (g) the image is real (R)or virtual (V), (h) inverted (I)or noninverted (NI)from O, and (i) on the same side of the mirror as the object O or on the opposite side. Fill in the missing information. Where only a sign is missing, answer with the sign.

32 through 38 37, 38 33, 35 Spherical refracting surfaces. An object Ostands on the central axis of a spherical refracting surface. For this situation, each problem in Table 34-5 refers to the index of refraction n1where the object is located, (a) the index of refraction n2on the other side of the refracting surface, (b) the object distance p, (c) the radius of curvature rof the surface, and (d) the image distance i. (All distances are in centimeters.) Fill in the missing information, including whether the image is (e) real (R)or virtual (V)and (f) on the same side of the surface as the objector on the opposite side.

(a) A luminous point is moving at speedV0toward a spherical mirror with a radius of curvaturer, along the central axis of the mirror. Show that the image of this point is moving at the speed

vI=-(r2p-r)2v0

Where,p is the distance of the luminous point from the mirror at any given time. Now assume the mirror is concave, withr=15cm.and letV0=5cm/s. FindV1when (b)p=30cm(far outside the focal point), (c) p=8.0cm(just outside the focal point), and (d)p=10mm(very near the mirror).

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