/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q31P (a) A luminous point is moving a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) A luminous point is moving at speedV0toward a spherical mirror with a radius of curvaturer, along the central axis of the mirror. Show that the image of this point is moving at the speed

vI=-(r2p-r)2v0

Where,p is the distance of the luminous point from the mirror at any given time. Now assume the mirror is concave, withr=15cm.and letV0=5cm/s. FindV1when (b)p=30cm(far outside the focal point), (c) p=8.0cm(just outside the focal point), and (d)p=10mm(very near the mirror).

Short Answer

Expert verified

a. The image is moving at the speed vI=-r2p-r2v0is shown in the part of the calculation.

Step by step solution

01

The given data:

  • The mirror is concave.
02

Determining the concept of speed of image:

For a given luminous object to be placed in front of a concave mirror, the image distance can be given using the lens equation. If the object is placed at infinity, then the image is formed at the focal point of the mirror, but if the object is within the focal point of the mirror, then the object formed is virtual. Now, the object when placed after the focal point before the radius of curvature, the image distance is far from the mirror, while for the object at a distance after the radius of curvature, the image distance is near to the mirror. Again, you know that the speed of an object is defined by its distance within the travel time. Thus, using this concept, you calculate the speed values.

Formulae:

The mirror equation is,

1f=1i+1p ….. (i)

Where, pis the pole, fis the focal length, and iis the image distance.

The speed of the object is,

v=dxdt ….. (ii)

Where,dx is the distance travelled by the object anddt is the time taken to travel.

03

(a) Determining the speed of the moving image as vI=-(r2p-r)2v0:

Using equation (i), the formula of image distance can be given as:

i=pfp-f ….. (iii)

But, you know that the focal length is half the radiusf curvature. That is given as:

f=r2

Substituting the above value in equation (iii), you get the value of image distance as:

i=pr2p-r2=pr2p-r

Now, the speed of the light is given using equation (ii) as follows:

vI=didt=ddtpr2p-r=2p-rddtpr-prddt2p-r2p-r2

Since, the speed of the object can be given using equation (ii) as follows:

V0=-dpdt

Thus, the speed of the luminous light can be given as:

vI=-r2p-r2v0

Hence, the image is moving at the speed vI=-r2p-r2v0is shown in the part of the calculation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

50 through 57 55, 57 53 Thin lenses. Object Ostands on the central axis of a thin symmetric lens. For this situation, each problem in Table 34-6 gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance localid="1662982946717" iand (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real (R) or virtual (V) , (d) inverted (I) from object O or non inverted (NI), and (e) on the same side of the lens as object Oor on the opposite side.

A movie camera with a (single) lens of focal length 75mmtakesa picture ofa person standing 27maway. If the person is180cmtall, what is the height of the image on the film?

A penguin waddles along the central axis of a concave mirror, from the focal point to an effectively infinite distance. (a) How does its image move? (b) Does the height of its image increase continuously, decrease continuously, or change in some more complicated manner?

58 through 67 61 59 Lenses with given radii. An object Ostands in front of a thin lens, on the central axis. For this situation, each problem in Table 34-7 gives object distance O, index of refraction n of the lens, radius of the nearer lens surface, and radius of the farther lens surface. (All distances are in centimeters.) Find (a) the image distance and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual , (d) inverted from the object Oor non-inverted , and (e) on the same side of the lens as object or on the opposite side.

An object is 30.0cmfrom a spherical mirror, along the mirror’s central axis. The mirror produces an inverted image with a lateral magnification of absolute value 0.500. What is the focal length of the mirror?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.