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(a) A luminous point is moving at speedV0toward a spherical mirror with a radius of curvaturer, along the central axis of the mirror. Show that the image of this point is moving at the speed

vI=-(r2p-r)2v0

Where,p is the distance of the luminous point from the mirror at any given time. Now assume the mirror is concave, withr=15cm.and letV0=5cm/s. FindV1when (b)p=30cm(far outside the focal point), (c) p=8.0cm(just outside the focal point), and (d)p=10mm(very near the mirror).

Short Answer

Expert verified

a. The image is moving at the speed vI=-r2p-r2v0is shown in the part of the calculation.

Step by step solution

01

The given data:

  • The mirror is concave.
02

Determining the concept of speed of image:

For a given luminous object to be placed in front of a concave mirror, the image distance can be given using the lens equation. If the object is placed at infinity, then the image is formed at the focal point of the mirror, but if the object is within the focal point of the mirror, then the object formed is virtual. Now, the object when placed after the focal point before the radius of curvature, the image distance is far from the mirror, while for the object at a distance after the radius of curvature, the image distance is near to the mirror. Again, you know that the speed of an object is defined by its distance within the travel time. Thus, using this concept, you calculate the speed values.

Formulae:

The mirror equation is,

1f=1i+1p ….. (i)

Where, pis the pole, fis the focal length, and iis the image distance.

The speed of the object is,

v=dxdt ….. (ii)

Where,dx is the distance travelled by the object anddt is the time taken to travel.

03

(a) Determining the speed of the moving image as vI=-(r2p-r)2v0:

Using equation (i), the formula of image distance can be given as:

i=pfp-f ….. (iii)

But, you know that the focal length is half the radiusf curvature. That is given as:

f=r2

Substituting the above value in equation (iii), you get the value of image distance as:

i=pr2p-r2=pr2p-r

Now, the speed of the light is given using equation (ii) as follows:

vI=didt=ddtpr2p-r=2p-rddtpr-prddt2p-r2p-r2

Since, the speed of the object can be given using equation (ii) as follows:

V0=-dpdt

Thus, the speed of the luminous light can be given as:

vI=-r2p-r2v0

Hence, the image is moving at the speed vI=-r2p-r2v0is shown in the part of the calculation.

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