91Ó°ÊÓ

Force on the block,${}^{F=12N}$

Weight of the block,${}^{W=5.0N}$

Coefficient of static friction, ${}^{{\mathrm{μ}}_s=0.60}$

Coefficient of kinetic friction, ${}^{{\mathrm{μ}}_k=0.40}$

The problem is based on Newton’s second law of motion which states that the rate of change of momentum of a body is equal in both magnitude and direction of the force acting on it.Use the Newton's 2nd law of motion along vertical and horizontal direction to check if the block will move or not. According to Newton's 2nd law of motion, a force applied to an object at rest causes it to accelerate in the direction of the force.

Formula:

$F_{net}=∑ma$

where, F is the net force, m is mass and a is an acceleration.

By using Newton’s 2nd law of motion along horizontal direction,

$$\begin{gathered} \mathrm{N}=\mathrm{F} \\ =12\mathrm{N} \end{gathered}$$

then, the maximum static frictional force of the block is,

$$\begin{gathered} f_{ma{x}_s}={\mathrm{μ}}_{s}N \\ =(0.60)\left(12\right) \\ =7.2N \end{gathered}$$

Therefore, as the $f_{ma{x}_s}>W$, block will not slide.

Since, the block does not move then force on the block is only ${}^{f_s}$and normal force from the wall is,

Hence, the force on the block from the wall is${}^{F_{BW}=(-12)\hat{i}+5\hat{j}}$