91影视

The mass, m = 66kilotonn

The 4% of the total mass is actually fissionable.

The expression to calculate the released energy is given as follows.

$\mathit{E}\mathbf{=}\mathit{m}{\mathit{c}}^{\mathbf{2}}$ 鈥︹�� (1)

The expression to calculate the number of fission is given as follows.

$\mathit{n}\mathbf{=}\frac{\mathbf{E}}{\mathbf{Q}}$ 鈥︹�� (2)

Here,Qis the energy per fission.

The expression to calculate the number of the fragment produced is given as follows.

n = 2n 鈥︹�� (3)

The typical energy released per fission is Q = 200MeV

The mass in megaton is $m=66脳{10}^{-3}\mathrm{Megatron}$.

Calculate the released energy.

Substitute $66脳{10}^{-3}\mathrm{Megatron}$for m and $2.6脳{10}^{28}\mathrm{Mev}/\mathrm{Meagatron}$for$c^2$into equation(1).

role="math" $$\begin{gathered} E=m{c}^2 \\ =66脳{10}^{-3}脳2.6脳{10}^{28} \\ =171.6脳{10}^{25} \\ =1.716脳{10}^{27}\mathrm{MeV} \end{gathered}$$

Calculate the number of the fission.

Substitute $1.716脳{10}^{27}\mathrm{MeV}$for E and 200MeV for Q into equation (2).

$$\begin{gathered} n=\frac{E}{Q} \\ =\frac{1.71脳{10}^{27}}{200} \\ =8.55脳{10}^{24} \end{gathered}$$

Since the 4% of the total mass is actually fissionable. Therefore, the original nuclei present is,

$\frac{8.6脳{10}^{24}}{0.04}=2.15脳{10}^{26}$

Calculate the mass of the uranium.

$$\begin{gathered} m_U=2.15脳{10}^{26}脳235脳u \\ =2.15脳{10}^{26}脳235脳1.66脳{10}^{-27} \\ =83.87kg \end{gathered}$$

By rounding up the value of the mass of the uranium is 84kg.

Hence, the mass of the Uranium is 84kg.

Calculate the number of the fragment.

Substitute $8.55脳{10}^{24}$for n into equation (3).

$$\begin{gathered} N=2n \\ =2脳8.55脳{10}^{24} \\ =17.1脳{10}^{24} \\ =1.71脳{10}^{25} \end{gathered}$$

Hence, the number of the produce fragment is $1.71脳{10}^{25}$.

It is given that, on average, each fission produces 2.5 neutrons. Therefore, number of the neutron released to the environment would be the 2.5 time the number of the fission.

$$\begin{gathered} N_n=2.5脳8.55脳{10}^{24} \\ =21.3脳{10}^{24} \\ =2.13脳{10}^{25} \end{gathered}$$

Hence, the number of the neutron released to the environment is $2.13脳{10}^{25}$.