/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6Q To make the newly discovered, ve... [FREE SOLUTION] | 91影视

91影视

To make the newly discovered, very large elements of the periodic table, researchers shoot a medium-size nucleus at a large nucleus. Sometimes a projectile nucleus and a target nucleus fuse to form one of the very large elements. In such a fusion, is the mass of the product greater than or less than the sum of the masses of the projectile and target nuclei?

Short Answer

Expert verified

The mass of the product is always less than the sum of masses of the projectile in nuclear fusion.

Step by step solution

01

Nuclear Fusion

Nuclear fusion is the process in which two lighter nuclei of different or same atoms form a heavier nucleus by combination is called nuclear fusion. A huge amount of energy is absorbed by lighter nuclei.

02

Whether the mass of the product is greater or less than the sum of masses of the projectile in nuclear fusion

The mass of the product is always less than the sum of masses of the projectile in nuclear fusion because some of the masses of the projectile are converted into energy. The mass of the projectile is converted to energy to form the product atom.

Therefore, the mass of the product is always less than the sum of masses of the projectile in nuclear fusion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the fission process

235U+n132Sn++3n

what number goes in (a) the elevated box (the superscript) and (b) the descended box (the value of Z)?

A thermal neutron (with approximately zero kinetic energy) is absorbed by a238Unucleus. How much energy is transferred from mass-energy to the resulting oscillation of the nucleus? Here are some atomic masses and neutron mass.

U237237.048723uU237238.050782uU237239.054287uU237240.056585un1.008664u

The neutron generation time tgenin a reactor is the average time needed for a fast neutron emitted in one fission event to be slowed to thermal energies by the moderator and then initiate another fission event. Suppose the power output of a reactor at timeis t=0is P0. Show that the power output a time tlater is P(t), whererole="math" localid="1661757074768" P(t)=P0tt/tgen and kis the multiplication factor. For constant power output,k=1.

The uncompressed radius of the fuel pellet of Sample Problem 43.05 is 20m. Suppose that the compressed fuel pellet 鈥渂urns鈥 with an efficiency of 10%鈥攖hat is, only 10% of the deuterons and 10% of the tritons participate in the fusion reaction of Eq. 43-15. (a) How much energy is released in each such micro explosion of a pellet? (b) To how much TNT is each such pellet equivalent? The heat of combustion of TNT is 4.6 MJ/kg . (c) If a fusion reactor is constructed on the basis of 100 micro explosions per second, what power would be generated? (Part of this power would be used to operate the lasers.)

The neutron generation time (see Problem 19) of a particular reactor is 1.3 ms .The reactor is generating energy at the rate of 1200.0 MW.To perform certain maintenance checks, the power level must temporarily be reduced to 350.00 MW. It is desired that the transition to the reduced power level take 2.6000 s. To what (constant) value should the multiplication factor be set to effect the transition in the desired time?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.