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If we split a nucleus into two smaller nuclei, with a release of energy, has the average binding energy per nucleon increased or decreased?

Short Answer

Expert verified

The binding energy per nucleon for smaller nuclei increases due to the split of the nucleus.

Step by step solution

01

Binding energy per Nucleon

The sum of the protons and neutrons in the nucleus is called the nucleons, and it is the same as the mass number of the atom. The energy required to separate each nucleon from the nuclear force of the nucleus is called the binding energy per nucleon. The binding energy per nucleon for an atom is given as:

Ebp=EbA

Here, Ebpis the binding energy per nucleon, Eb is the binding energy, and A is the mass number of atoms.

02

Whether average binding energy per nucleon of smaller nuclei increased or decreased

The repulsive force between protons in smaller nuclei becomes less due to the reduced number of protons. In contrast, the nuclear force remains the same, so the overall nuclear force increases and smaller nuclei become more stable than large nuclei. As the nuclear force for smaller nuclei increases, more energy is required to separate the nucleons of smaller nuclei, and binding energy per nucleon for smaller nuclei increases.

We can also see from the formula of binding energy per nucleon that binding energy per nucleon varies inversely with the mass number of nuclei. The mass number of smaller nuclei is small, so the binding energy per nucleon of smaller nuclei becomes more than heavier nuclei.

Therefore, the binding energy per nucleon for smaller nuclei increases due to the split of the nucleus

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Most popular questions from this chapter

Calculate the Coulomb barrier height for two7Linuclei that are fired at each other with the same initial kinetic energy K.(Hint: Use Eq. 42-3 to calculate the radii of the nuclei.)

The fission properties of the plutonium isotope Pu239are very similar to those of U235. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1.0 kg of purePu239 undergo fission?

In an atomic bomb, energy release is due to the uncontrolled fission of plutonium Pu239(or U235). The bomb’s rating is the magnitude of the released energy, specified in terms of the mass of TNT required to produce the same energy release. One megaton of TNT releases 2.6×1028MeVof energy. (a) Calculate the rating, in tons of TNT, of an atomic bomb containing 95 kg of Pu239, of which 2.5 kg actually undergoes fission. (See Problem 4.) (b) Why is the other 92.5 kg of Pu239needed if it does not fission?

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Find role="math" localid="1661942719139" ∆KKfor each of the following acting as the stationary atom:

(b) hydrogen,

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The isotope 235Udecays by alpha emission with a half-life of 7×108y. It also decays (rarely) by spontaneous fission, and if the alpha decay did not occur, its half-life due to spontaneous fission alone would be 3×1017y.

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