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• The half-life of alpha emission is $t_{1/2}=7脳{10}^{8}y$.
• The half-life for spontaneous fission is $T=3脳{10}^{17}y$.
• The mass of the uranium 235 is m = 1g

Radioactive decay is the process of decaying of protons from the nucleus and variation in the mass number of the atom. The number of protons increases by one unit due to beta decay and no change in the mass number of the atom, while the number of protons changes by two units and mass number by four units for alpha decay.

The rate of spontaneous fission decay is given as:

$R\mathit{=}\frac{\mathit{m}{\mathit{N}}_{\mathit{A}}\mathit{}\mathit{I}\mathit{n}\mathit{2}}{{\mathit{M}}_{\mathit{u}}\mathit{T}}$

Here $N_A$is the Avogadro constant and its value is $6.023脳{10}^{23}\mathrm{mol}/\mathrm{g}$.

Substitute all the values in the above equation.

$$\begin{gathered} \mathrm{R}=\frac{\left(1\mathrm{g}\right)\left(6.023脳{10}^{23}\mathrm{mol}/\mathrm{g}\right)\mathrm{In}2}{\left(235\mathrm{mol}\right)\left(3脳{10}^{17}\mathrm{y}\right)\left({\displaystyle \frac{365\mathrm{day}}{1\mathrm{y}}}\right)} \\ \mathrm{R}=16.22\mathrm{fission}/\mathrm{day} \\ \mathrm{R}鈮�16\mathrm{fission}/\mathrm{day} \end{gathered}$$

The number of alpha decay for spontaneous fission is calculated as:

$n=\frac{T}{t}$

Substitute all the values in the above equation.

$$\begin{gathered} n=\frac{3脳{10}^{17}y}{7脳{10}^{8}y} \\ n=4.3脳{10}^8 \end{gathered}$$

Therefore, the number of alpha decay for spontaneous fission is $4.3脳{10}^8$.