/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11PE Question: Find the components of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: Find the components of \({v_{tot}}\) along the \(x\)- and \(y\)-axes in Figure 3.55.

Figure: The two velocities \({{\rm{v}}_{\rm{A}}}\) and \({{\rm{v}}_{\rm{B}}}\) add to give a total \({{\rm{v}}_{{\rm{tot}}}}\).

Short Answer

Expert verified

The \(x\) component of \({v_{tot}}\) is \(4.409\;{\rm{m/s}}\) and \(y\) component of \({v_{tot}}\) is \(5.072\;{\rm{m/s}}\).

Step by step solution

01

Understanding resolution of vectors

Resolution of vectors is the process of breaking a vector into two or more vectors along distinct directions, in order to ascertain the magnitude and the direction of vector components that together generate the same impact as a single vector.

Given data:

  • \({v_{tot}} = 6.72\;{\rm{m/s}}\).
02

Calculating horizontal component of total velocity

Figure: the components and the resultant

The angle between\(x\)-axis and\({v_{tot}}\)is

\(\begin{array}{c}\alpha = \left( {26.5^\circ } \right) + \left( {22.5^\circ } \right)\\ = 49^\circ \end{array}\)

The horizontal component of\({v_{tot}}\)is

\({v_{to{t_x}}} = {v_{tot}}\cos \alpha \)

Substituting\(6.72\;{\rm{m/s}}\)for\({v_{tot}}\)and\(49^\circ \)for\(\alpha \), we have

\(\begin{array}{c}{v_{to{t_x}}} = \left( {6.72\;{\rm{m/s}}} \right) \times \cos \left( {49^\circ } \right)\\ = 4.409\;{\rm{m/s}}\end{array}\)

Hence, the \(x\) component of \({v_{tot}}\) is \(4.409\;{\rm{m/s}}\).

03

Calculating vertical component of horizontal velocity

The vertical component of\({v_{tot}}\)is

\({v_{to{t_y}}} = {v_{tot}}\sin \alpha \)

Substituting\(6.72\;{\rm{m/s}}\)for\({v_{tot}}\)and\(49^\circ \)for\(\alpha \), we have

\(\begin{array}{c}{v_{to{t_y}}} = \left( {6.72\;{\rm{m/s}}} \right) \times \sin \left( {49^\circ } \right)\\ = 5.072\;{\rm{m/s}}\end{array}\)

Hence, the \(y\) component of \({v_{tot}}\) is \(5.072\;{\rm{m/s}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If an airplane pilot is told to fly 123 km in a straight line to get from San Francisco to Sacramento, explain why he could end up anywhere on the circle . What other information would he need to get to Sacramento?

Answer the following questions for projectile motion on level ground assuming negligible air resistance (the initial angle being neither \(0^\circ \) nor \(90^\circ \)):

(a) Is the velocity ever zero?

(b) When is the velocity a minimum? A maximum?

(c) Can the velocity ever be the same as the initial velocity at a time other than at \(t = 0\)?

(d) Can the speed ever be the same as the initial speed at a time other than at \(t = 0\)?

(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a\(32^\circ \)ramp at a speed of\(40.0{\rm{ m}}/{\rm{s}}\)\(\left( {144{\rm{ km}}/{\rm{h}}} \right)\). How many buses can he clear if the top of the takeoff ramp is at the same height as the bus tops and the buses are\(20.0{\rm{ m}}\)long?

(b) Discuss what your answer implies about the margin of error in this act—that is, consider how much greater the range is than the horizontal distance he must travel to miss the end of the last bus. (Neglect air resistance.)

Find the following for path A in Figure,

(a) the total distance traveled, and

(b) the magnitude and direction of the displacement from start to finish.

The various lines represent paths taken by different people walking in a city. All blocks are120 mon a side.

The cannon on a battleship can fire a shell a maximum distance of\(32.0{\rm{ km}}\).

(a) Calculate the initial velocity of the shell.

(b) What maximum height does it reach? (At its highest, the shell is above\(60\% \)of the atmosphere—but air resistance is not really negligible as assumed to make this problem easier.)

(c) The ocean is not flat, because the Earth is curved. Assume that the radius of the Earth is \(6.37 \times {10^3}{\rm{ km}}\). How many meters lower will its surface be \(32.0{\rm{ km}}\) from the ship along a horizontal line parallel to the surface at the ship? Does your answer imply that error introduced by the assumption of a flat Earth in projectile motion is significant here?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.