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(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500渭颁 charge and flies due west at a speed of 660 m/s over the Earth鈥檚 south magnetic pole, where the 8.00105Tmagnetic field points straight up. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect.

Short Answer

Expert verified

(a) The magnitude of the force is 2.64108Nand it points towards the earth.

(b) The effect of this force is insignificant.

Step by step solution

01

Given information

The charge on the supersonic jet is \({\bf{q = 0}}.5{\bf{00}}\;{\bf{\mu C}}\left( {\frac{{{\bf{1}}{{\bf{0}}^{{\bf{ - 6}}}}\;{\bf{C}}}}{{{\bf{1}}\;{\bf{\mu C}}}}} \right) = 5.00 \times {\bf{1}}{{\bf{0}}^{{\bf{ - }}7}}\;{\bf{C}}\)

The magnetic field strength of the earth鈥檚 south pole isB=8.00105T

The speed of the supersonic jet isv=660m/s

02

Step 2:Definition of magnetic force

The magnetic force is a consequence of the electromagnetic force, one of the four fundamental forces of nature, and is caused by the motion of charges. Two objects containing a charge with the same direction of motion have a magnetic attraction force between them. Similarly, objects with charges moving in opposite directions have a repulsive force between them.

03

Step 3:Determining the magnetic force exerted on the plane

(a)

To determine the magnetic force exerted on the plane, we will use the equation,

F=qvBsin()鈥︹赌︹赌︹赌︹赌︹赌︹赌︹赌︹赌︹赌(1)

where is the angle between the direction in which the plane moves, to the west, and the direction of the earth's magnetic field, to the north. This angle will be .

The direction of the force will be determined by the right-hand rule. By pointing the thumb to the left, the direction of the velocity, and pointing the fingers upwards, the direction of the earth's magnetic field, the force will be towards the earth.

Substituting the given values in the above expression will give,

F=(5107C)(660m/s)(8.00105T)sin(90)=2.64108N

Therefore, the magnitude of the force is 2.64108Nand it points toward the earth.

(b)

Considering the mass of the plane, we can surely say that the effect of this force is insignificant.

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Most popular questions from this chapter

Consider using the torque on a current-carrying coil in a magnetic field to detect relatively small magnetic fields (less than the field of the Earth, for example). Construct a problem in which you calculate the maximum torque on a current-carrying loop in a magnetic field. Among the things to be considered are the size of the coil, the number of loops it has, the current you pass through the coil, and the size of the field you wish to detect. Discuss whether the torque produced is large enough to be effectively measured. Your instructor may also wish for you to consider the effects, if any, of the field produced by the coil on the surroundings that could affect detection of the small field.

(a) The hot and neutral wires supplying DC power to a light-rail commuter train car 800Aand are separated by 75.0cm What is the magnitude and direction of the force between50.0mof these wires? (b) Discuss the practical consequences of this force, if any.

Make a drawing and use RHR-2 to find the direction of the magnetic field of a current loop in a motor (such as in Figure 22.34). Then show that the direction of the torque on the loop is the same as produced by like poles repelling and unlike poles attracting.

Measurements affect the system being measured, such as the current loop in Figure 22.56

(a) Estimate the field the loop creates by calculating the field at the center of a circular loop 20.0 cm in diameter carrying 5.00A

(b) What is the smallest field strength this loop can be used to measure if its field must alter the measured field by less than0.0100%?

Repeat Exercise 22.3 for a positive charge.

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