91影视

• Force =12,000 N.
• The angle =2.00掳.

Calculate the net force applied in the horizontal direction as:

$\begin{array}{c}{\mathbf{F}}_{\mathbf{n}\mathbf{e}\mathbf{t}\mathbf{,}\mathbf{x}}\mathbf{=}\mathbf{T}\mathbf{c}\mathbf{o}\mathbf{s}\mathbf{胃}\mathbf{鈭�}\mathbf{T}\mathbf{c}\mathbf{o}\mathbf{s}\mathbf{胃}\\ \mathbf{=}\mathbf{0}\end{array}$

Here, T is the tension in the rope, and 胃 is the angle made by the rope with the horizontal.

Write the expression for the net force applied in the vertical direction and equate it to zero as:

$\begin{array}{c}{\mathbf{F}}_{\mathbf{n}\mathbf{e}\mathbf{t}\mathbf{,}\mathbf{y}}\mathbf{=}{\mathbf{F}}_{\mathbf{鈯�}}\mathbf{鈭�}\mathbf{T}\mathbf{s}\mathbf{i}\mathbf{n}\mathbf{胃}\mathbf{鈭�}\mathbf{T}\mathbf{s}\mathbf{i}\mathbf{n}\mathbf{胃}\mathbf{=}\mathbf{0}\\ {\mathbf{F}}_{\mathbf{鈯�}}\mathbf{=}\mathbf{2}\mathbf{T}\mathbf{s}\mathbf{i}\mathbf{n}\mathbf{胃}\end{array}$

Here ${\mathbf{F}}_{\mathbf{鈯�}}$is the force exerted perpendicular to the center of the rope.

Substitute 12000 N for T and $2掳$for 胃 in the above expression, and we get,

$\begin{array}{c}{F}_{鈯�}=2脳12000\text{鈥凬}脳\sin 2^{掳}\\ =24000\text{鈥凬}脳0.0349\\ =837.6\text{鈥凬}\end{array}$

Hence, the force exerted perpendicular to the rope is 837.6 N.

$T=\frac{F_{鈯�}}{2\sin 胃}$

Substitute 837.6 N for $F_{鈯�}$and $7掳$for 胃 in the above expression, and we get,

$\begin{array}{c}T=\frac{837.6\text{鈥凬}}{2\sin 7^{掳}}\\ =\frac{837.6\text{鈥凬}}{2脳0.12187}\\ =3436.45\text{鈥凬}\end{array}$

Hence, the force exerted on the car is 3436.45 N.