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The \(1.00-\mathrm{cm}-\) long second hand on a watch rotates smoothly. a. What is its angular velocity? b. What is the speed of the tip of the hand?

Short Answer

Expert verified
The angular velocity of the hand is \(\frac{2\pi}{60}\) radians per second. The speed of the tip of the hand is \(0.01m \times \frac{2\pi}{60}rad/s\).

Step by step solution

01

Calculate the angular velocity

Firstly, we calculate the angular velocity. Angular velocity \(\omega\) is defined as the rate of change of angular displacement with respect to time. For a second hand that rotates smoothly, it completes a full circle (an angle of \(2\pi\) radians) every 60 seconds. Thus, the angular velocity \(\omega\) is given by \(2\pi\) radians divided by 60 seconds. Therefore, \(\omega = \frac{2\pi}{60}\) radians per second.
02

Convert radius to meters

To calculate the speed of the tip of the hand, we first need to make sure units are consistent. The length of the second hand, 1cm, must be converted from cm to meters: \(1cm = 0.01m\). This will be the radius \(r\) used in the calculation.
03

Calculate the speed of the tip of the hand

We then use the formula for speed in circular motion, \(v = r\omega\). Substituting for \(r = 0.01m\) (from step 2) and \(\omega = \frac{2\pi}{60}rad/s\) (from step 1), we get \(v = 0.01m \times \frac{2\pi}{60}rad/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
In the world of physics, circular motion refers to the movement of an object along the circumference of a circle or rotation along a circular path. It's vital to understand that even though an object may be moving at a constant speed, if it is on a circular path, its velocity is not constant because its direction is continuously changing.

For an object moving in uniform circular motion, the velocity vector is always tangent to the path of the object. The second-hand of a watch is a great example of this kind of motion as it sweeps around its pivot point, maintaining a steady speed. This is considered uniform because the angular speed remains constant.

Centripetal Force & Acceleration

These antics of the second hand aren't just a whimsical dance but rather the result of a centripetal force which acts towards the center of the circular path. This force is what keeps the hand in circular motion rather than flying off in a straight line. The associated centripetal acceleration is directed towards the center of the circle and is necessary for maintaining the circular motion. If this force ceased, the second hand would follow Newton's first law and move off in a straight line path.
Radians
Radians are the units of angular measure used in the language of mathematics and physics when dealing with circular motion. They provide a direct measure of the angle in terms of the radius of the circle.

One radian is defined as the angle created when you take the radius and lay it along the circumference of the circle; the arc length equal to the radius corresponds to an angle of one radian. The beauty of radians lies in their ability to simplify calculations involving angular velocities and other quantities in circular motion since they relate directly to the radius.

Converting Degrees to Radians

Since there are 360 degrees in a circle and about 6.28318 radians (which is 2π) in a circle, we can convert between these units. The formula for this conversion is Radians = Degrees × (π/180). This conversion is useful when swapping between units or interpreting angular measurements in different contexts.
Speed of a Point in Circular Motion
Speed of a point in circular motion is a fascinating concept because it combines linear and angular elements to describe the motion. When we discuss the speed of an object traveling in a circle, we are often referring to its tangential speed - this is the linear speed of a point on the outer edge of the circle, moving along the tangent at that point.

The formula to calculate this speed is a simple product of radius (r) and angular velocity (ω): Speed = r × ω. Given that angular velocity is measured in radians per second, and the radius is a linear measure, this formula gives us the speed of a point on the object in meters per second.

The Relation Between Linear and Angular Speed

It's important to note that the tangential speed (linear speed) is highest at the outermost points of the object in circular motion and is directly proportional to the distance from the center. This is why the tip of the second hand of a watch moves faster than a point closer to the center; it has a greater distance to cover in the same period of time. The formula that we use incorporates this relationship by multiplying the angular speed with the radial distance from the pivot point.

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Most popular questions from this chapter

The bigclaw snapping shrimp named-it has one big claw that snaps shut with remarkable speed. The part of the claw that moves rotates through a \(90^{\circ}\) angle in \(1.3 \mathrm{ms} .\) If we assume that the claw is \(1.5 \mathrm{cm}\) long and that it undergoes a constant angular acceleration: a. What is the angular acceleration in \(\mathrm{rad} / \mathrm{s}^{2}\) ? b. What is the final angular speed of the claw? c. What is the tangential acceleration of the tip of the claw? d. How fast is the tip of the claw moving at the end of its motion?

A bicycle with 0.80-m-diameter tires is coasting on a level road at \(5.6 \mathrm{m} / \mathrm{s}\). A small blue dot has been painted on the tread of the rear tire. a. What is the angular speed of the tires? b. What is the speed of the blue dot when it is \(0.80 \mathrm{m}\) above the road? c. What is the speed of the blue dot when it is \(0.40 \mathrm{m}\) above the road?

A \(1.5 \mathrm{kg}\) block and a \(2.5 \mathrm{kg}\) block are attached to opposite ends of a light rope. The rope hangs over a solid, frictionless pulley that is \(30 \mathrm{cm}\) in diameter and has a mass of \(0.75 \mathrm{kg}\). When the blocks are released, what is the acceleration of the lighter block?

Hold your arm outstretched so that it is horizontal. Estimate the mass of your arm and the position of its center of gravity. What is the gravitational torque on your arm in this position, computed around the shoulder joint?

U.S. nickels have a mass of \(5.00 \mathrm{g}\) and are \(1.95 \mathrm{mm}\) thick. If you stack 3 nickels on a table, how far above the table is their center of gravity?

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