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A Ferris wheel on a California pier is \(27 \mathrm{m}\) high and rotates once every 32 seconds. When the wheel starts turning, you are at the very top. a. What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between \(0^{\circ}\) and \(360^{\circ} .\) b. What is your speed \(v ?\)

Short Answer

Expert verified
a. The angular position after 75 seconds is approximately \(281.25^\circ\). \nb. The speed is approximately \(2.65 m/s\).

Step by step solution

01

Calculate the Angular Speed

Firstly, we need to find the angular speed, \(\omega\), of the Ferris wheel. The wheel makes one complete revolution (which is \(360^\circ\) or \(2\pi\) radians) every 32 seconds. So, we can express \(\omega\) as \(\frac{2\pi \text{ radians}}{32 \text{ seconds}} = \frac{\pi}{16} \text{ rad/sec}\) since \(\omega = \frac{\theta}{t}\).
02

Determine the Angular Displacement After a Certain Time

In order to find the angular position 75 seconds after it starts turning, we multiply the angular speed by this time: \(\theta = \omega \times t = \frac{\pi}{16} \text{ rad/sec} \times 75 \text{ seconds} = \frac{15\pi}{32} \text{ radians}= 281.25^\circ \) where the conversion factor \(\frac{180^\circ}{\pi \text{ radians}}\) has been used to convert radians to degrees.
03

Calculate the Linear Speed

The linear speed \(v\) of an object moving in a circular path is given by \(v = \omega r\) where \(r = 27 m/2 = 13.5 m\) is the radius of the Ferris wheel. Substituting the values we find: \(v = \omega r = \frac{\pi}{16} \text{ rad/sec} \times 13.5 m = 2.65 m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Angular Speed
The notion of angular speed, denoted as \(\omega\), is pivotal when discussing circular motion, such as the rotation of a Ferris wheel. Angular speed refers to the rate at which an object rotates around a fixed point or axis. It tells us how quickly the object covers an angular distance. In the context of our Ferris wheel problem, we calculate angular speed by dividing the total angle of rotation (one full turn being \(2\pi\) radians) by the time it takes to make that turn. Hence, we have:\
\
\[\omega = \frac{2\pi \text{ radians}}{32 \text{ seconds}} = \frac{\pi}{16} \text{ rad/sec}\]\
\
To further understand this, imagine the second hand of a clock. It has a higher angular speed compared to the minute hand, because it makes a full rotation (\(360^\circ\) or \(2\pi\) radians) in less time (60 seconds). The Ferris wheel, on the other hand, rotates once every 32 seconds, which in our example equates to an angular speed of \(\frac{\pi}{16}\) rad/sec.\
\
Understanding angular speed is crucial as it is a foundational concept not only in Ferris wheel physics problems but also for anything that involves rotational movements, including gears in a machine, tires on a car, or the Earth rotating on its axis.
Angular Displacement in Circular Motion
The concept of angular displacement is another crucial element in understanding circular motion. It describes the angle through which a point or line has been rotated in a specified direction around a specified axis. If you're sitting in one of the Ferris wheel's cabins, your angular displacement is how far you've rotated from your starting point.\
\
In mathematical terms, once we know the angular speed \(\omega\), we can determine how far the Ferris wheel has rotated after a given time (\(t\)) by multiplying the two:\
\
\[\theta = \omega \times t\]\
\
For example, after 75 seconds, the angular displacement from the starting point at the top for the Ferris wheel in question is \(\frac{15\pi}{32}\) radians. By converting radians to degrees, we understand that the position is 281.25 degrees from the start, almost completing a full circle, but not quite.\
\
Angular displacement has direct applications in many fields, such as engineering, where it helps in the design of mechanisms like robotic arms or wind turbines, which rely on precise rotational movements.
Circular Motion Dynamics
When an object moves in a circle, such as a cabin on a Ferris wheel, it experiences what we call circular motion. This type of motion possesses specific properties and follows certain physical laws, making it an interesting case study in physics. One key feature of circular motion is that even if the speed of the object is constant, its velocity is not, because its direction is continually changing as it moves around the circle.\
\
Furthermore, an object in circular motion is subject to centripetal force, which acts towards the center of the circle, keeping the object on its circular path. The relationship between linear speed \(v\), radius \(r\), and angular speed \(\omega\) is crucial. It’s given by the formula:\
\
\[v = \omega r\]\
\
In the case of our Ferris wheel, with a radius of 13.5 meters, the passengers experience a linear speed calculated using the previously found angular speed. Specifically, the linear speed for the Ferris wheel is 2.65 m/s. This property is not only essential in the analysis of amusement rides, but also in any system involving rotational movement, such as satellites orbiting a planet or a disc in a DVD player.\
\
The concepts of circular motion are central to many aspects of physics and engineering, as they explain the behavior of objects moving in circular paths and help inform the design and functioning of various mechanical and astronomical systems.

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