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A bicycle with 0.80-m-diameter tires is coasting on a level road at \(5.6 \mathrm{m} / \mathrm{s}\). A small blue dot has been painted on the tread of the rear tire. a. What is the angular speed of the tires? b. What is the speed of the blue dot when it is \(0.80 \mathrm{m}\) above the road? c. What is the speed of the blue dot when it is \(0.40 \mathrm{m}\) above the road?

Short Answer

Expert verified
The angular speed of the tires is \(14 \mathrm{rad/s}\). The speed of the blue dot when it is \(0.80 \mathrm{m}\) above the road is \(5.6 \mathrm{m/s}\), and when it is \(0.40 \mathrm{m}\) above the road is \(3.8 \mathrm{m/s}\).

Step by step solution

01

Calculate Angular Speed

Angular speed can be calculated by rearranging the equation \(v = r\omega\) to \(\omega = v / r\). Given that the speed of the bicycle is \(5.6 \mathrm{m/s}\) and the radius of the tire (which is half its diameter) is \(0.4 \mathrm{m}\), plug these values into the equation to find \(\omega\).
02

Calculate the Speed of the Dot At \(0.80\) Meters Above the Road

At the top of the tire, the blue dot is \(0.80\) meters from the road, this being the same as the diameter of the tire, the distance to the center of rotation is \(0.4\) meters. So the linear speed of the dot is still \(r\omega\) at \(0.80\) meters above the ground. Given that \(r = 0.4 \mathrm{m}\), plug these values into the equation \(\omega\).
03

Calculate the Speed of the Dot At \(0.40\) Meters Above the Road

At \(0.40\) meters above the ground, the blue dot is on the edge of the tire and moving horizontally. The distance to the center of rotation is the radius of the circle that the dot is moving along, which can be calculated by Pythagorean Theorem: \(r = \sqrt{(0.4^2 - 0.2^2) \mathrm{m}}\). Plug these values into the equation \(v = r\omega\) to calculate the speed of the blue dot.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity, often symbolized as \(\omega\), is a measure of how quickly an object rotates around a fixed point or axis. It is the rate of change of angular position of an object and is usually expressed in units of radians per second (rad/s). The concept is crucial in fields like physics and engineering, where it helps describe the rotational motion of objects.

To calculate the angular speed of a rotating object like a bicycle tire, you use the relationship between linear speed \(v\), radius \(r\), and angular speed \(\omega\) given by the equation \(v = r\omega\). For our bicycle example, the tire has a linear speed of 5.6 m/s and a radius of 0.4 meters (half of its diameter), leading us to the equation \(\omega = \frac{v}{r}\), which computes the angular velocity of the tires.

Understanding angular velocity is useful for a variety of practical applications, such as figuring out how the speed of different points on a rotating object changes, which is directly linked to our next concept, linear speed.
Linear Speed
Linear speed is the measure of how fast an object is moving along a straight path. It is the distance traveled per unit of time and is generally measured in meters per second (m/s) in the SI unit system. While angular velocity considers rotation, linear speed focuses on the straight-line motion.

In the context of a rotating tire, every point on the edge of the tire moves with the same angular velocity, but their linear speeds can vary depending on their distance from the axis of rotation. The linear speed of any point on the tire can be calculated using the formula \(v = r\omega\), where \(r\) is the radius from the center of rotation to that point. This formula explains why points on the outer edge of a tire move faster than points closer to the center: they cover more distance in the same amount of time.

For instance, the blue dot painted on the surface of the tire has the same angular velocity as the tire itself, but its linear speed is determined by its radius from the axis of rotation at any given moment.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in geometry which states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as \(a^2 + b^2 = c^2\), where \(c\) is the hypotenuse.

This theorem is particularly useful when solving problems involving triangles and circular motion. For example, to calculate the speed of a point at a certain height on a rotating wheel, you may need to determine the radius of the circular path that the point follows at that height. Using the Pythagorean Theorem, one could find the necessary radius to plug into our linear speed equation \(v = r\omega\).

In our bicycle problem, when the blue dot is 0.40 meters above the road, the radius of the circle it traces out (which is necessary to determine its linear speed) can be calculated using the Pythagorean Theorem by considering the height above the ground and the radius of the complete tire. This demonstrates the theorem's relevance in analyzing the motion of points travelling in circular paths.

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Most popular questions from this chapter

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The lightweight wheel on a road bike has a moment of inertia of \(0.097 \mathrm{kg} \cdot \mathrm{m}^{2} .\) A mechanic, checking the alignment of the wheel, gives it a quick spin; it completes 5 rotations in 2.0 s. To bring the wheel to rest, the mechanic gently applies the disk brakes, which squeeze pads against a metal disk connected to the wheel. The pads touch the disk \(7.1 \mathrm{cm}\) from the axle, and the wheel slows down and stops in \(1.5 \mathrm{s} .\) What is the magnitude of the friction force on the disk?

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