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The crankshaft in a race car goes from rest to 3000 rpm in 2.0 s. a. What is the crankshaft's angular acceleration? b. How many revolutions does it make while reaching 3000 rpm?

Short Answer

Expert verified
a. The crankshaft's angular acceleration is \(157.08 {\, \rm rad/s^2}\). b. The crankshaft makes 50 revolutions while reaching 3000 rpm.

Step by step solution

01

Convert Rotational Speed to Angular Velocity

Before calculating angular acceleration, convert the given rotational speed from revolutions per minute (rpm) to radians per second, because standard units of angular velocity are rad/s. Use the conversion factor that \(1{\, \rm rpm} \approx 0.1047 {\, \rm rad/s}\). Therefore, the angular velocity, \(\omega\), is \(3000{\, \rm rpm} * 0.1047{\, \rm rad/s/rpm} = 314.16{\, \rm rad/s}\).
02

Calculate Angular Acceleration

Now calculate the angular acceleration, \(\alpha\), using the formula \(\alpha = \dfrac{\Delta \omega}{\Delta t}\). This is the final angular velocity minus the initial angular velocity, divided by the time it takes for that change. Because the crankshaft starts from rest, the initial angular velocity is 0. So the angular acceleration would be \(\alpha = \dfrac{314.16{\, \rm rad/s}}{2.0{\, \rm s}} = 157.08 {\, \rm rad/s^2}\).
03

Calculate Displacement in Radians

Calculate the total angular displacement in radians of the crankshaft during the 2.0 s period. Use the equation \(\theta = \omega_{i}t + \frac{1}{2}\alpha t^2\). Because the crankshaft starts from rest, \(\omega_{i} = 0\). Therefore, the angular displacement is \(\theta = \dfrac{1}{2} * 157.08 {\, \rm rad/s^2} * (2.0{\, \rm s})^2 = 314.16 {\, \rm rad}\).
04

Convert Displacement to Revolutions

Convert the angular displacement from radians to revolutions. Use the conversion factor that \(1{\, \rm revolution} = 2\pi {\, \rm rad}\). Therefore, the number of revolutions is \(\frac{314.16{\, \rm rad}}{2\pi {\, \rm rad/revolution}} = 50 {\, \rm revolutions}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Kinematics
Rotational kinematics is the branch of physics that describes the motion of objects rotating about an axis. This includes not only the speed at which an object rotates, known as angular velocity, but also how this speed changes over time—a concept known as angular acceleration. Just as linear kinematics involves displacement, velocity, and acceleration, rotational kinematics deals with angular displacement, angular velocity, and angular acceleration, where angular displacement refers to the change in angle, angular velocity refers to how fast the angle changes, and angular acceleration describes how quickly the angular velocity itself changes.

A common example used to explain these concepts is the motion of a crankshaft in an engine. If the crankshaft accelerates uniformly from rest to a certain rotational speed, one can study this behavior using rotational kinematics. The formulas for rotational kinematics are akin to their linear counterparts but adapted for rotation around an axis rather than motion along a straight line. For instance, just like one might use the formula \( s = ut + \frac{1}{2}at^2 \) to describe linear motion, in rotational kinematics, a similar formula, \( \theta = \omega_{i}t + \frac{1}{2}\alpha t^2 \) is used, where \( \theta \) represents the angular displacement, \( \omega_{i} \) is the initial angular velocity (often zero when starting from rest), and \( \alpha \) is the angular acceleration.
Angular Velocity
Angular velocity, denoted by the Greek letter \( \omega \), is a measure of how quickly an object rotates about a fixed axis. It is usually expressed in radians per second (rad/s). Since radians are a measure of angle, angular velocity quantifies the rate at which an angle is swept out over time. This is a crucial concept in rotational kinematics, as it provides a direct measure of how fast something is spinning. This can be comparable to linear velocity, which measures how fast an object is moving along a path.

When faced with an exercise where the angular velocity needs to be determined, such as finding out how fast a crankshaft rotates, it is essential to convert the units appropriately. For example, the common unit of car engine speed is revolutions per minute (rpm), which can be converted to rad/s by using the conversion ratio \(1{\, \rm rpm} \approx 0.1047{\rm \, rad/s}\). Once the angular velocity is in the correct units, it can be used in various equations to analyze the rotational motion further, such as determining the angular acceleration or the time it takes to reach a certain angular velocity from rest.
Angular Displacement
Angular displacement is a measure of the angle through which a point or line has been rotated in a specified sense about a specified axis. It is an analogue of linear displacement, which measures the distance traveled. Angular displacement is measured in radians, where one complete revolution equals \(2\pi\) radians. This quantity is important in defining how far an object has rotated, which is different from the path length a point on the object has traveled in space.

To understand angular displacement, consider the spinning crankshaft from our previous example. When calculating how many revolutions it makes while reaching a certain angular velocity, it is necessary to determine the angular displacement. This is done using the formula \( \theta = \omega_{i}t + \frac{1}{2}\alpha t^2\) and converting the displacement from radians to revolutions using the conversion \(1{\rm \,revolution} = 2\pi{\rm \,rad}\). Angular displacement helps in visualizing the actual rotational progress of an object, which complements the quantitative analysis of its rotation provided by angular velocity and acceleration.

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Most popular questions from this chapter

A bowling ball is far from uniform. Lightweight bowling balls are made of a relatively low-density core surrounded by a thin shell with much higher density. A 7.0 lb \((3.2 \mathrm{kg})\) bowling ball has a diameter of \(0.216 \mathrm{m} ; 0.196 \mathrm{m}\) of this is a \(1.6 \mathrm{kg}\) core, surrounded by a \(1.6 \mathrm{kg}\) shell. This composition gives the ball a higher moment of inertia than it would have if it were made of a uniform material. Given the importance of the angular motion of the ball as it moves down the alley, this has real consequences for the game. a. Model a real bowling ball as a \(0.196-\mathrm{m}\) -diameter core with mass \(1.6 \mathrm{kg}\) plus a thin \(1.6 \mathrm{kg}\) shell with diameter \(0.206 \mathrm{m}\) (the average of the inner and outer diameters). What is the total moment of inertia? b. How does your answer in part a compare to the moment of inertia of a uniform \(3.2 \mathrm{kg}\) ball with diameter \(0.216 \mathrm{m} ?\)

A small grinding wheel has a moment of inertia of \(4.0 \times 10^{-5} \mathrm{kg} \cdot \mathrm{m}^{2} .\) What net torque must be applied to the wheel for its angular acceleration to be \(150 \mathrm{rad} / \mathrm{s}^{2} ?\)

A reasonable estimate of the moment of inertia of an ice skater spinning with her arms at her sides can be made by modeling most of her body as a uniform cylinder. Suppose the skater has a mass of \(64 \mathrm{kg} .\) One-eighth of that mass is in her arms, which are \(60 \mathrm{cm}\) long and \(20 \mathrm{cm}\) from the vertical axis about which she rotates. The rest of her mass is approximately in the form of a 20 -cm-radius cylinder. a. Estimate the skater's moment of inertia to two significant figures. b. If she were to hold her arms outward, rather than at her sides, would her moment of inertia increase, decrease, or remain unchanged? Explain.

Two children are playing tetherball, in which a ball at the end of a cord spins around a pole. After a really good hit, the ball makes three complete revolutions in \(2.0 \mathrm{s}\). What is the angular speed of the ball?

A man in a barrel walking competition is moving along smoothly, with his barrel moving forward at \(1.0 \mathrm{m} / \mathrm{s}\). a. Think about how the man moves his legs. Is he walking forward or backward? b. From the point of view of the top of the barrel-the man's walking surface- how fast is he walking?

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