/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 The bigclaw snapping shrimp name... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The bigclaw snapping shrimp named-it has one big claw that snaps shut with remarkable speed. The part of the claw that moves rotates through a \(90^{\circ}\) angle in \(1.3 \mathrm{ms} .\) If we assume that the claw is \(1.5 \mathrm{cm}\) long and that it undergoes a constant angular acceleration: a. What is the angular acceleration in \(\mathrm{rad} / \mathrm{s}^{2}\) ? b. What is the final angular speed of the claw? c. What is the tangential acceleration of the tip of the claw? d. How fast is the tip of the claw moving at the end of its motion?

Short Answer

Expert verified
The angular acceleration is approximately \(2.76 \times 10^{8}\) rad/s², the final angular speed is roughly 359 rad/s, the tangential acceleration of the tip is about 4140 m/s², and the final tangential speed is approximately 5.39 m/s.

Step by step solution

01

Converting the initial given quantities

Convert angular displacement from degrees to radians: \(1 rad = 180^{\circ} / \pi\), so \(90^{\circ}\) equals \( \frac{90 \times \pi}{180} = \frac{\pi}{2}\) rad. Convert time from milliseconds to seconds: \(1.3 ms = 1.3 \times 10^{-3} s\). Convert length from centimeters to meters: \(1.5 cm = 0.015 m\).
02

Compute Angular Acceleration

Use the formula for angular acceleration: \(\alpha = \frac{2(\theta - iω t)}{t^2}\), where \(α\) is the angular acceleration, \(θ\) is the final angular displacement, \(iω\) is the initial angular velocity, and \(t\) is the time. Considering \(iω = 0\) since the claw starts from rest, the formula becomes \(\alpha = \frac{2 \times (\pi/2) }{(1.3 \times 10^{-3})^2}\) rad/s².
03

Compute Final Angular Speed

Use the formula for final angular speed: \(fω = iω + α \times t\), where \(fω\) is the final angular speed, \(iω\) the initial angular speed, \(α\) the angular acceleration, and \(t\) the time period. Considering \(iω = 0\) the formula becomes \(fω = \alpha \times 1.3 \times 10^{-3}\) rad/s.
04

Compute Tangential Acceleration

Use the formula for tangential acceleration: \(a_t = α \times r\), where \(α\) is the angular acceleration and \(r\) is the length of the claw. Rearanging and substituting we get \(a_t = α \times 0.015 m\).
05

Compute Tangential Speed at the End of Motion

Use the formula for tangential speed: \(v = r \times ω\), where \(v\) is the tangential speed, \(r\) is the length of the claw, and \(ω\) is the angular speed. Rearranging and substituting we get \(v = 0.015 m \times fω\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Kinematics
Rotational kinematics involves the description of the motion of rotating bodies without considering the forces that bring about the motion. It is analogous to linear kinematics but with rotation-specific parameters like angular position, velocity, and acceleration.

In our context, the snapping shrimp's claw rotates through an angle, giving us a clear scenario of rotational motion. To describe this motion, we'd first convert any linear measurements into their angular counterparts. For instance, we change the angle from degrees to radians because radians are the standard unit of angular measure in physics. This conversion is crucial for applying formulas in rotational kinematics.

One such formula relates angular displacement (the angle through which an object has rotated) to the angular velocity (rate of change of angular displacement) and the angular acceleration (rate of change of angular velocity). In mathematical terms, the relation is often given by the equation \(\theta = i\theta + i\theta t + \frac{1}{2}\theta t^2\), where \(\theta\) is the angular displacement, \(i\theta\) is the initial angular velocity, and \(t\) is the time interval. If a body starts from rest, as in our exercise, \(i\theta = 0\) and the formula simplifies accordingly.
Angular Displacement
Angular displacement refers to the difference in the angular position of a rotating body. In our example, the shrimp's claw rotates through a certain angle, representing its angular displacement. It's essential to work in radians to determine angular displacement, which is why the conversion from degrees to radians is carried out in the first step of the solution.

We also need to consider the initial and final positions of rotation to calculate the angular displacement appropriately. The angular displacement assists in determining other rotational quantities such as angular velocity and acceleration. In the case of constant angular acceleration, the angular displacement is directly proportional to the square of the time taken for the given motion, if it started from rest.
Tangential Acceleration
Tangential acceleration is the linear acceleration that occurs along a circular path and is always directed perpendicular to the radius at any given point. It is related to the angular acceleration by the radius of the path taken by the object in motion. In our exercise, to compute the tangential acceleration of the claw's tip, we use the formula \(a_t = \theta \times r\), where \(a_t\) is tangential acceleration, \(r\) is the radius, in this case, the length of the claw, and \(\theta\) is the angular acceleration.

This calculation essentially takes a rotational motion concept and translates it into linear terms that describe how quickly the point on the outside edge of the rotation (like the tip of the shrimp's claw) is accelerating. Understanding tangential acceleration is vital for analyzing moving parts in machinery, wheels, or even celestial bodies orbiting in space.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.