91Ó°ÊÓ

We are given that the temperature at the centre of the sun is approximately ${10}^7\mathrm{K}$and the concentration of electrons is approximately ${10}^{32}$per cubic meter.

Calculating the fermi temperature for the electron gas at the center of the Sun to check if the given statement is correct or not.

The Fermi temperature for the electron gas at the center of the Sun is given by,

$T_F=\frac{E_F}{k}$

The fermi energy of electrons can be expressed in terms of free electron density as follows,

${\mathrm{Î\mu }}_F=\frac{h^2}{8m_e}{\left(\frac{3N}{\mathrm{Ï€}V}\right)}^{\frac{2}{3}}$

Putting the values, we get

$$\begin{gathered} T_F=\frac{1}{k}\frac{h^2}{8m_e}{\left(\frac{3N}{\mathrm{π}V}\right)}^{\frac{2}{3}} \\ {T}_F=\frac{{\left(6.63×{10}^{-34}\mathrm{J}·\mathrm{s}\right)}^2}{\left(1.38×{10}^{-23}\mathrm{J}/\mathrm{K}\right)\left(8\right)\left(9.1×{10}^{-31}\mathrm{kg}\right)}{\left(\frac{3\left({10}^{32}{\mathrm{m}}^{-3}\right)}{\mathrm{π}}\right)}^{\frac{2}{3}} \\ =9.1×{10}^6\mathrm{K} \end{gathered}$$

The Fermi temperature is of the same order of magnitude as the temperature of the Sun $\left({10}^7\mathrm{K}\right)$.

Here, the temperature T is not much less than or greater than $T_F$. Hence, the approximation is not very accurate.

Due to this reason, the gas cannot be treated as degenerate at $T=0$, and ordinary classical ideal gas at $T≫T_F$.