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Use the result of the previous problem to calculate the freezing temperature of seawater.

Short Answer

Expert verified

Therefore, the freezing temperature of seawater is-2.167°C

Step by step solution

01

Given information

From the previous problem we have:

T-T0=-NBkT02L

02

Explanation

from the previous problem, we have

T-T0=-NBkT02L

but,NBk=nBRr, so

T-T0=-nBRT02L

Where,

Tois the freezing temperature of water

nBis the number of moles of salt

Lis the fusion latent energy of water and is given as L=333.7×103J

03

Calculations

We have 35 grammes of salt in one kilogram of water because sea water contains calcium and sodium, which have an average molar mass of 30 g/mol, hence in 35g the number of moles are

nB=35g30g/mol=1.167mol

Substitute the values,

role="math" localid="1647204325114" T-T0=-(1.167mol)(8.314J/mol·K)(273K)2333.7×103J=-2.167KT=273K-2.167K=270.833KT=-2.167°C

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