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Go through the arithmetic to verify that diamond becomes more stable than graphite at approximately 15 kbar.

Short Answer

Expert verified

The diamond is more stable than graphite at 15 kbar.

Step by step solution

01

Step 1. Given information

We can choose the reference value because the Gibbs free energy of one mole of diamond is 2900 J higher than the Gibbs free energy of one mole of graphite. Let the graphite's Gibbs free energy be 0 for the sake of simplicity.

02

Step 2. Concept

Therefore the two equations of the lines drawn in fig 5.15 are

Gg=VgP

Gd=VdP+2.9kJ

Where,

Ggis Gibbs energy of graphite

Gd is Gibbs energy of diamond

Vgis volume of graphite

Vd is volume of diamond

We need to prove that the diamond becomes more stable than graphite at pressures of 15 kbar, and to do so, we need to identify the intersection of the two curves, set Gg equals to Gd to get

VgP=VdP+2.9kJ

03

Step 3. Calculations

Solve for P to get,

P(Vg-Vd)=2.9 kJ

P=2.9kJVg-Vd

the molar volume of graphite is Vg=5.31×10-6m3 and the molar volume of diamond is Vd=3.42×10-6m3

Substitute the values and solve
P=2900J5.31×10-6m3-3.42×10-6m3P=1.534×109PaP=1.534×104barP=15.34kbar

We used 1bar=104kbar

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where " width="9">

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