/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 The National Council of Small Bu... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The National Council of Small Businesses is interested in the proportion of small businesses that declared Chapter 11 bankruptcy last year. Since there are so many small businesses, the National Council intends to estimate the proportion from a random sample. Let \(p\) be the proportion of small businesses that declared Chapter 11 bankruptcy last year. (a) If no preliminary sample is taken to estimate \(p,\) how large a sample is necessary to be \(95 \%\) sure that a point estimate \(\hat{p}\) will be within a distance of 0.10 from \(p ?\) (b) In a preliminary random sample of 38 small businesses, it was found that six had declared Chapter 11 bankruptcy. How many more small businesses should be included in the sample to be \(95 \%\) sure that a point estimate \(\hat{p}\) will be within a distance of 0.10 from \(p ?\)

Short Answer

Expert verified
(a) A sample size of 97 is required. (b) An additional 14 businesses should be surveyed.

Step by step solution

01

Determine the critical value

Since we want a 95% confidence level, first look up the z-score for a 2.5% tail (because it's two-tailed for confidence interval centers), which is 1.96. So, the critical value is 1.96.
02

Use the formula for sample size without preliminary estimate

When no preliminary estimate is available for the proportion, a conservative approach is to use a proportion of 0.5 for maximum variance. We'll use the formula for sample size: \[ n = \left( \frac{Z}{E} \right)^2 \times p(1-p) \]where \( n \) is the sample size, \( Z \) is the z-score (1.96), \( E \) is the margin of error (0.10), and \( p \) is 0.5. Substitute these values: \[ n = \frac{(1.96)^2 \times 0.5 \times 0.5}{(0.10)^2} = \frac{3.8416 \times 0.25}{0.01} = 96.04 \]So, the sample size needed is approximately 97.
03

Preliminary sample result interpretation

In the preliminary sample of 38 small businesses, 6 declared bankruptcy. Calculate the sample proportion \( \hat{p} \): \[ \hat{p} = \frac{6}{38} \approx 0.1579 \] Now, we'll use this proportion for the sample size calculation.
04

Use redesigned formula for additional sample size

Use the formula with the preliminary proportion: \[ n = \left( \frac{Z}{E} \right)^2 \times \hat{p}(1-\hat{p}) \]where \( \hat{p} = 0.1579 \). Substitute the values: \[ n = \frac{(1.96)^2 \times 0.1579 \times (1 - 0.1579)}{(0.10)^2} = \frac{3.8416 \times 0.1579 \times 0.8421}{0.01} \approx 51.67 \]Since we already have a sample of 38, the additional needed is approximately \( 52 - 38 = 14 \) more small businesses.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval provides a range of values that is likely to contain the true value of an unknown population parameter, such as the proportion of small businesses declaring Chapter 11 bankruptcy. In statistical analysis, confidence intervals are essential because they help you understand the precision of your estimate. Whenever you hear about a '95% confidence interval,' it means you can be 95% certain that the actual proportion falls within this range.

The magic of confidence intervals lies in their ability to convey not just a single point estimate, but a range which is more informative about the uncertainty surrounding the point. The width of a confidence interval is directly related to the sample size and variability of the data. As in our exercise, a critical z-value of 1.96 is often used for a 95% confidence level. This z-value corresponds to the confidence level and ensures that the interval is constructed such that 95% of similar samples would capture the true parameter.

Thus, in practice, determining a proper sample size ensures that the resulting interval estimate ( \[hat{p}\] ) is precise, meaning within an acceptable distance from the true unknown proportion.
Proportion Estimation
Proportion estimation involves calculating the proportion of a population with a specific characteristic. In our case, it's about estimating how many small businesses filed for Chapter 11 bankruptcy.

To estimate a proportion ( \[hat{p}\] ) accurately, one often starts with a sample. The estimation task involves the use of statistical formulas, considering factors like sample size, confidence level, and margin of error. Here, the formula used is \[n = \left( \frac{Z}{E} \right)^2 \times \hat{p}(1-\hat{p})\] , where:
  • \(Z\) is the critical value (z-score), for 95% confidence, it's 1.96.
  • \(E\) is the margin of error, desired to be within 0.10 of the true proportion.
  • \(hat{p}\) is the sample proportion previously calculated, in this case, \(0.1579\).

In scenarios lacking initial data, it's common to use 0.5 as the estimated proportion for a conservative and maximal sample size. However, if preliminary data is available, such as in our exercise where \(hat{p} \approx 0.1579\) collected from 6 businesses out of 38, it refines the sample size estimation, reducing it significantly for better efficiency and precision.
Chapter 11 Bankruptcy
Chapter 11 bankruptcy is a form of bankruptcy restructuring designed for businesses to rehabilitate their operations and finances. It allows companies to stay in business while restructuring debts under court supervision.

For small businesses, filing for Chapter 11 can offer a chance to renegotiate terms with creditors, reorganize operations, and return to profitability without going through liquidation. This can be crucial in maintaining jobs, business continuance, and value over the loss.

However, it's also an indication of financial distress, which makes studies like the National Council’s significant. Understanding how frequently small businesses resort to Chapter 11 helps inform strategies for financial support and preventative measures. By estimating the proportion, stakeholders assess the health of the small business sector and build interventions to aid struggling businesses effectively. Thus, determining the accurate proportion of small businesses declaring Chapter 11 is invaluable for economic policy-making and aiding that crucial part of the economy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A random sample of medical files is used to estimate the proportion \(p\) of all people who have blood type B. (a) If you have no preliminary estimate for \(p,\) how many medical files should you include in a random sample in order to be \(85 \%\) sure that the point estimate \(\hat{p}\) will be within a distance of 0.05 from \(p ?\) (b) Answer part (a) if you use the preliminary estimate that about 8 out of 90 people have blood type \(\mathrm{B}\) (Reference: Manual of Laboratory and Diagnostic Tests by F. Fischbach).

Jerry tested 30 laptop computers owned by classmates enrolled in a large computer science class and discovered that 22 were infected with keystroke- tracking spyware. Is it appropriate for Jerry to use his data to estimate the proportion of all laptops infected with such spyware? Explain.

A random sample of 328 medical doctors showed that 171 have a solo practice (Source: Practice Patterns of General Internal Medicine, American Medical Association). (a) Let \(p\) represent the proportion of all medical doctors who have a solo practice. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p\). Give a bricf explanation of the meaning of the interval. (c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice? What is the margin of error based on a \(95 \%\) confidence interval?

In a combined study of northern pike, cutthroat trout, rainbow trout, and lake trout, it was found that 26 out of 855 fish died when caught and released using barbless hooks on flies or lures. All hooks were removed from the fish (Source: \(A\) National Symposium on Catch and Release Fishing, Humboldt State University Press). (a) Let \(p\) represent the proportion of all pike and trout that die (i.e., \(p\) is the mortality rate) when caught and released using barbless hooks. Find a point estimate for \(p\). (b) Find a \(99 \%\) confidence interval for \(p,\) and give a brief explanation of the meaning of the interval. (c) Is the normal approximation to the binomial justified in this problem? Explain.

Lorraine was in a hurry when she computed a confidence interval for \(\mu\). Because \(\sigma\) was not known, she used a Student's \(t\) distribution. However, she accidentally used degrees of freedom \(n\) instead of \(n-1 .\) Was her confidence interval longer or shorter than one found using the correct degrees of freedom \(n-1 ?\) Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.