/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 You don't need to be rich to buy... [FREE SOLUTION] | 91Ó°ÊÓ

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You don't need to be rich to buy a few shares in a mutual fund. The question is, "How reliable are mutual funds as investments?" That depends on the type of fund you buy. The following data are based on information taken from Morningstar, a mutual fund guide available in most libraries. A random sample of percentage annual returns for mutual funds holding stocks in aggressive- growth small companies is shown next. $$\begin{aligned} &\begin{array}{ccccccccc} -1.8 & 14.3 & 41.5 & 17.2-16.8 & 4.4 & 32.6 & -7.3 & 16.2 & 2.8 & 34.3 \end{array}\\\ &\begin{array}{llllllll} -10.6 & 8.4 & -7.0 & -2.3-18.5 & 25.0 & -9.8 & -7.8 & -24.6 & 22.8 \end{array} \end{aligned}$$ Use a calculator to verify that \(s^{2} \approx 348.43\) for the sample of aggressive growth small company funds. Another random sample of percentage annual returns for mutual funds holding value (i.e., market under priced) stocks in large companies is shown next. $$\begin{aligned} &\begin{array}{ccccccccc} 16.2 & 0.3 & 7.8 & -1.6 & -3.8 & 19.4 & -2.5 & 15.9 & 32.6 & 22.1 & 3.4 \end{array}\\\ &\begin{array}{ccccccccc} -0.5-8.3 & 25.8 & -4.1 & 14.6 & 6.5 & 18.0 & 21.0 & 0.2 & -1.6 \end{array} \end{aligned}$$ Use a calculator to verify that \(s^{2} \approx 137.31\) for value stocks in large companies. Test the claim that the population variance for mutual funds holding aggressive-growth small stocks is larger than the population variance for mutual funds holding value stocks in large companies. Use a \(5 \%\) level of significance. How could your test conclusion relate to the question of reliability of returns for each type of mutual fund?

Short Answer

Expert verified
Insufficient evidence to conclude that aggressive-growth stocks are more unreliable than value stocks.

Step by step solution

01

Define the Hypotheses

We want to test if the variance of aggressive-growth small stocks is greater than the variance of value stocks in large companies. Let \( \sigma_1^2 \) be the variance of aggressive-growth small stocks, and \( \sigma_2^2 \) be the variance of value stocks in large companies. The null hypothesis \( H_0 \) is \( \sigma_1^2 \leq \sigma_2^2 \), and the alternative hypothesis \( H_a \) is \( \sigma_1^2 > \sigma_2^2 \).
02

Calculate the Test Statistic

Since we're comparing variances, the test statistic follows an F-distribution. The test statistic is given by \( F = \frac{s_1^2}{s_2^2} \), where \( s_1^2 = 348.43 \) for aggressive-growth small stocks and \( s_2^2 = 137.31 \) for value stocks in large companies. Compute \( F = \frac{348.43}{137.31} \approx 2.54 \).
03

Determine the Critical Value

The degrees of freedom for the variances are \( df_1 = n_1 - 1 \) and \( df_2 = n_2 - 1 \), where \( n_1 \) and \( n_2 \) are the sample sizes for each group. Assume both samples have 20 data points each (based on provided data). Therefore, \( df_1 = df_2 = 19 \). For a 5% level of significance, find the critical value \( F_{0.05,19,19} \) from the F-distribution table. It is approximately 2.54.
04

Compare Test Statistic to Critical Value

Compare the calculated test statistic \( F = 2.54 \) to the critical value 2.54. Since \( F = 2.54 \) is equal to the critical value, we are at the border of the acceptance and rejection regions.
05

Make a Decision

Since the test statistic is equal to the critical value, we have insufficient evidence to reject the null hypothesis at the 5% level of significance. This suggests that there isn't enough statistical evidence to claim that the variance for aggressive-growth small stocks is larger than for value stocks in large companies.
06

Conclusion on Reliability

Variances measure the spread of returns; high variance implies more risk and unreliability. Since we cannot conclude that the aggressive-growth stocks have a higher variance, we can't definitively say they are more unreliable than the value stocks based on this test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Variance
Population variance is a fundamental concept in statistics that measures how much the values in a population differ from the mean of that population. It is denoted by the symbol \( \sigma^2 \) and represents the average of the squared differences from the mean. Calculating it involves taking each data point, finding the difference from the mean, squaring that difference, and then averaging those squared differences. Population variance is crucial because it gives insight into the variability or dispersion of a dataset. In the context of the exercise, we are looking at the variances of two different types of mutual funds. Having a grasp on variance helps in understanding the risk associated with the investment. Large variance indicates that the data points are spread out over a wide range of values, which generally indicates more risk but also potentially more opportunities for high returns.
F-distribution
The F-distribution is a probability distribution that arises frequently in hypothesis testing, especially when comparing two variances. An F-distribution is used in the F-test to understand if two populations have different variances. It is asymmetrical and depends on two different degrees of freedom parameters, which reflect the sample sizes of the two groups being compared. In the exercise you're dealing with, we calculate an F-statistic by the ratio of the variances from aggressive-growth funds and value funds. A higher F-value can indicate that there is more variability between the groups than within them. Understanding the F-distribution is key to conducting tests on variance and determining if the observed differences are statistically significant.
Level of Significance
The level of significance, often denoted as \( \alpha \), is a critical concept in hypothesis testing. It represents the threshold at which you are willing to accept the risk of rejecting a true null hypothesis—a situation known as a Type I error. A common level of significance used in most tests is 5%, which is set as \( \alpha = 0.05 \). This implies that we are willing to accept a 5% chance of incorrectly rejecting the null hypothesis. In the context of our variance test, using a 5% level of significance means we will only reject the null hypothesis if the calculated F-statistic is extremely unlikely under the null hypothesis, specifically if it falls in the top 5% of the F-distribution.
Null and Alternative Hypotheses
In any hypothesis test, we start with formulating a null hypothesis \( H_0 \) and an alternative hypothesis \( H_a \). The null hypothesis represents the default statement that there is no effect or no difference, while the alternative hypothesis suggests the opposite. In this exercise, the null hypothesis is that the population variance of aggressive-growth small stocks is less than or equal to the variance of value stocks, \( \sigma_1^2 \leq \sigma_2^2 \). This means we assume there is no greater risk up front. The alternative hypothesis states that the population variance of aggressive-growth small stocks is greater, \( \sigma_1^2 > \sigma_2^2 \). Establishing these hypotheses allows us to use statistical tests to determine which is more likely given our data, thereby aiding us in making informed conclusions about the reliability and risk of investments.

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Most popular questions from this chapter

A random sample of leading companies in South Korea gave the following percentage yields based on assets (see reference in Problem 7): $$\begin{array}{cc} 2.5 & 2.0 & 4.5 & 1.8 & 0.5 & 3.6 & 2.4 \\ 0.2 & 1.7 & 1.8 & 1.4 & 5.4 &1.1 \end{array}$$ Use a calculator to verify that \(s^{2}=2.247\) for these South Korean companies. Another random sample of leading companies in Sweden gave the following percentage yields based on assets: $$\begin{array}{ccccccccc} 2.3 & 3.2 & 3.6 & 1.2 & 3.6 & 2.8 & 2.3 & 3.5 & 2.8 \end{array}$$ Use a calculator to verify that \(s^{2}=0.624\) for these Swedish companies. Test the claim that the population variance of percentage yields on assets for South Korean companies is higher than that for companies in Sweden. Use a \(5 \%\) level of significance. How could your test conclusion relate to an economist's question regarding volatility of corporate productivity of large companies in South Korea compared with that in Sweden?

Charlotte is doing a study on fraud and identity theft based both on source (checks, credit cards, debit cards, online banking/finance sites, other) and on gender of the victim. Describe the sampling method appropriate for a test of independence regarding source of fraud and gender.

Please provide the following information. (a) What is the level of significance? State the null and alternate hypotheses. (b) Find the value of the chi-square statistic for the sample. Are all the expected frequencies greater than \(5 ?\) What sampling distribution will you use? What are the degrees of freedom? (c) Find or estimate the \(P\) -value of the sample test statistic. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories? (e) Interpret your conclusion in the context of the application. Ecology: Fish The Fish and Game Department stocked Lake Lulu with fish in the following proportions: \(30 \%\) catfish, \(15 \%\) bass, \(40 \%\) bluegill, and \(15 \%\) pike. Five years later it sampled the lake to see if the distribution of fish had changed. It found that the 500 fish in the sample were distributed as follows. \(\begin{array}{cccc}\text { Catfish } & \text { Bass } & \text { Bluegill } & \text { Pike } \\ 120 & 85 & 220 & 75\end{array}\) In the 5 -year interval, did the distribution of fish change at the 0.05 level?

When using the \(F\) distribution to test two variances, is it essential that each of the two populations be normally distributed? Would it be all right if the populations had distributions that were mound-shaped and more or less symmetric?

Economics: Profits per Employee How productive are U.S. workers? One way to answer this question is to study annual profits per employee. A random sample of companies in computers (I), aerospace (II), heavy equipment (III), and broadcasting (IV) gave the following data regarding annual profits per employee (units in thousands of dollars) (Source: Forbes Top Companies, edited by J. T. Davis, John Wiley and Sons).$$\begin{array}{cccc}\mathbf{I} & \mathbf{I I} & \mathbf{I I I} & \mathbf{I V} \\\27.8 & 13.3 & 22.3 & 17.1 \\\23.8 & 9.9 & 20.9 & 16.9 \\\14.1 & 11.7 & 7.2 & 14.3 \\\8.8 & 8.6 & 12.8 & 15.2 \\\11.9 & 6.6 & 7.0 & 10.1 \end{array}$$. Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the four types of companies? Use a \(5 \%\) level of significance.

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