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Economics: Profits per Employee How productive are U.S. workers? One way to answer this question is to study annual profits per employee. A random sample of companies in computers (I), aerospace (II), heavy equipment (III), and broadcasting (IV) gave the following data regarding annual profits per employee (units in thousands of dollars) (Source: Forbes Top Companies, edited by J. T. Davis, John Wiley and Sons).$$\begin{array}{cccc}\mathbf{I} & \mathbf{I I} & \mathbf{I I I} & \mathbf{I V} \\\27.8 & 13.3 & 22.3 & 17.1 \\\23.8 & 9.9 & 20.9 & 16.9 \\\14.1 & 11.7 & 7.2 & 14.3 \\\8.8 & 8.6 & 12.8 & 15.2 \\\11.9 & 6.6 & 7.0 & 10.1 \end{array}$$. Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the four types of companies? Use a \(5 \%\) level of significance.

Short Answer

Expert verified
We do not reject the null hypothesis, as the F-statistic is less than the critical value.

Step by step solution

01

Understanding Hypotheses

First, we need to define the null and alternative hypotheses for this ANOVA test. The null hypothesis \((H_0)\) states that there is no difference in mean annual profits per employee across the four industry groups, i.e., \( \mu_{I} = \mu_{II} = \mu_{III} = \mu_{IV} \). The alternative hypothesis \((H_a)\) is that at least one mean is different.
02

Calculate Group Means

Compute the mean profit per employee for each of the four groups. This is done by summing the profits in each column and dividing by the number of data points in that column. For instance, for group I: \( \text{Mean}_{I} = \frac{27.8 + 23.8 + 14.1 + 8.8 + 11.9}{5} = 17.28 \) thousand dollars. Repeat for the other groups.
03

Calculate Overall Mean

Next, compute the overall mean of all the profit data combined. This involves summing all the profits and dividing by the total number of observations (20 in total): \(\text{Overall Mean} = \frac{27.8 + 23.8 + 14.1 + 8.8 + 11.9 + 13.3 + 9.9 + 11.7 + 8.6 + 6.6 + 22.3 + 20.9 + 7.2 + 12.8 + 7.0 + 17.1 + 16.9 + 14.3 + 15.2 + 10.1}{20}\).
04

Compute Sum of Squares

Calculate the "Sum of Squares Between" (SSB) and "Sum of Squares Within" (SSW) the groups. SSB measures variability due to the interaction between the groups, while SSW measures variability within each group. Use the formula for SSB: \[ SSB = n \sum_{i=1}^{k}(\bar{x}_i - \bar{x})^2 \]where \( n \) is the number of observations per group, \( \bar{x}_i \) is the mean of each group, and \( \bar{x} \) is the overall mean. SSW is calculated by:\[ SSW = \sum_{i=1}^{k} \sum_{j=1}^{n}(x_{ij} - \bar{x}_i)^2 \]
05

Calculate Degrees of Freedom

Determine the degrees of freedom for both the numerator (between groups) and the denominator (within groups). The degrees of freedom between (dfB) is \( k - 1 \), where \( k \) is the number of groups. Therefore, \( dfB = 4 - 1 = 3 \). The degrees of freedom within (dfW) is \( N - k \), where \( N \) is the total number of observations. Therefore, \( dfW = 20 - 4 = 16 \).
06

Find F-statistic

Calculate the F-statistic using:\[ F = \frac{MSB}{MSW} = \frac{SSB/dfB}{SSW/dfW} \]This gives a ratio of the variance between the groups to the variance within the groups. Simplify and solve this expression to find the F-statistic.
07

Determine Critical Value and Conclusion

Refer to an F-distribution table to find the critical value based on dfB, dfW, and \( \alpha = 0.05 \). Compare the calculated F-statistic to this critical value. If the F-statistic is greater than the critical value, reject the null hypothesis. Otherwise, do not reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

null hypothesis
In statistics, the null hypothesis is a fundamental concept, especially when conducting experiments or hypothesis tests like ANOVA. The null hypothesis, often denoted as \( H_0 \), is a statement that there is no effect or no difference among the groups being studied. In our context of analyzing profits per employee across different industries, the null hypothesis is that there are no differences in the mean annual profits per employee across the four types of companies: computers, aerospace, heavy equipment, and broadcasting.

The ANOVA test scrutinizes whether the variability between these groups is more than you would expect by chance alone. The null hypothesis is very important because it sets the stage for testing. It’s our default assumption, and our job is to determine whether the evidence from our data is strong enough to reject this assumption in favor of an alternative, which would be that at least one industry differs from the others in terms of profits per employee.

If we decide to reject the null hypothesis, it implies there is a statistically significant effect or difference that merits further investigation. Conversely, if we do not reject \( H_0 \), it suggests that any observed differences could be due to random variability rather than a real effect.
F-statistic
The F-statistic is a crucial part of ANOVA as it determines the ratio of variance between the groups to the variance within the groups. This ratio helps us understand whether the groups differ significantly by comparing the variance among the means of each group to the variance of data points within each group.

The formula to compute the F-statistic is:\[ F = \frac{\text{MSB}}{\text{MSW}} = \frac{\frac{SSB}{\text{dfB}}}{\frac{SSW}{\text{dfW}}} \]where \( \text{MSB} \) is the mean square between the groups and \( \text{MSW} \) is the mean square within the groups, utilizing the sum of squares values and corresponding degrees of freedom for each.
  • SSB (Sum of Squares Between): Measures variability due to the interaction between different groups.
  • SSW (Sum of Squares Within): Captures variability within each group.
After calculating the F-statistic, it’s compared to a critical value from the F-distribution table (accounting for the degrees of freedom and the significance level of 0.05). If the F-statistic is greater than the critical value, it's an indication to reject the null hypothesis, suggesting that at least one group’s mean is statistically significantly different from the others. This type of comparison offers a quantitative decision-making tool in hypothesis testing.
degrees of freedom
Degrees of freedom are an essential component of the hypothesis testing process. They refer to the number of independent values or quantities which can be assigned to a statistical distribution. In ANOVA, degrees of freedom are used in determining the critical values from the F-distribution.

There are two main types of degrees of freedom in ANOVA:
  • Degrees of Freedom Between (dfB): This value is calculated as \( k - 1 \), where \( k \) is the number of groups. It represents the number of ways the group means can vary relative to the overall mean.
  • Degrees of Freedom Within (dfW): This is computed as \( N - k \), where \( N \) is the total number of observations. It reflects the variation among data points within each group.
For instance, in our exercise with four groups (industries) and a total of 20 observations, the dfB would be \( 4 - 1 = 3 \), and dfW would be \( 20 - 4 = 16 \).
Degrees of freedom are intuitive as they represent the number of comparisons or independent pieces of information available to estimate another piece of information (like variance). They play a crucial role in determining critical values from the statistical tables used in hypothesis testing, helping to establish whether we should accept or reject the null hypothesis based on our data's evidence.

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Most popular questions from this chapter

Please provide the following information. (a) What is the level of significance? State the null and alternate hypotheses. (b) Find the value of the chi-square statistic for the sample. Are all the expected frequencies greater than \(5 ?\) What sampling distribution will you use? What are the degrees of freedom? (c) Find or estimate the \(P\) -value of the sample test statistic. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories? (e) Interpret your conclusion in the context of the application. Accounting Records: Benford's Law Benford's Law states that the first nonzero digits of numbers drawn at random from a large complex data file have the following probability distribution (Reference: American Statistical Association, Chance, Vol. \(12,\) No. \(3,\) pp. \(27-31 ;\) see also the Focus Problem of Chapter 9). Suppose that \(n=275\) numerical entries were drawn at random from a large accounting file of a major corporation. The first nonzero digits were recorded for the sample. Use a \(1 \%\) level of significance to test the claim that the distribution of first nonzero digits in this accounting file follows Benford's Law.

Does the \(x\) distribution need to be normal in order to use the chi-square distribution to test the variance? Is it acceptable to use the chi-square distribution to test the variance if the \(x\) distribution is simply mound- shaped and more or less symmetric?

A researcher forms three blocks of students interested in taking a history course. The groups are based on grade point average (GPA). The first group consists of students with a GPA less than \(2.5,\) the second group consists of students with a GPA between 2.5 and \(3.1,\) and the last group consists of students with a GPA greater than 3.1 History courses are taught in three ways: traditional lecture, small-group collaborative method, and independent study. The researcher randomly assigns 10 students from each block to sections of history taught each of the three ways. Sections for each teaching style then have 10 students from each block. The researcher records the scores on a common course final examination administered to each student. Draw a flow chart showing the design of this experiment. Does the design fit the model for randomized block design?

In general, is the \(F\) distribution symmetric? Can values of \(F\) be negative?

Zane is interested in the proportion of people who recycle each of three distinct products: paper, plastic, electronics. He wants to test the hypothesis that the proportion of people recycling each type of product differs by age group: \(12-18\) years old, \(19-30\) years old, \(31-40\) years old, over 40 years old. Describe the sampling method appropriate for a test of homogeneity regarding recycled products and age.

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