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Do you prefer paintings in which the people are fully clothed? This question was asked by a professional survey group on behalf of the National Arts Society (see reference in Problem 30). A random sample of \(n_{1}=59\) people who are conservative voters showed that \(r_{1}=45\) said yes. Another random sample of \(n_{2}=62\) people who are liberal voters showed that \(r_{2}=36\) said yes. Does this indicate that the population proportion of conservative voters who prefer art with fully clothed people is higher than that of liberal voters? Use \(\alpha=0.05\).

Short Answer

Expert verified
The test shows that conservative voters have a higher preference for fully clothed art (reject \( H_0 \)).

Step by step solution

01

Set up Hypotheses

We are testing whether the proportion of conservative voters who prefer paintings with fully clothed people is higher than that of liberal voters. Let \( p_1 \) be the proportion of conservative voters, and \( p_2 \) be the proportion of liberal voters. The null hypothesis \( H_0 \) is \( p_1 \leq p_2 \), and the alternative hypothesis \( H_a \) is \( p_1 > p_2 \).
02

Calculate Sample Proportions

The sample proportion of conservative voters is calculated as \( \hat{p}_1 = \frac{r_1}{n_1} = \frac{45}{59} \). Likewise, the sample proportion of liberal voters is \( \hat{p}_2 = \frac{r_2}{n_2} = \frac{36}{62} \).
03

Find the Pooled Sample Proportion

The pooled proportion \( \hat{p} \) is used to calculate the standard error. It is given by \( \hat{p} = \frac{r_1 + r_2}{n_1 + n_2} = \frac{45 + 36}{59 + 62} \).
04

Calculate the Standard Error

The standard error for the difference in proportions is calculated using the formula: \[ SE = \sqrt{ \hat{p} (1 - \hat{p}) \left(\frac{1}{n_1} + \frac{1}{n_2}\right) } \]
05

Compute the Test Statistic

The test statistic \( Z \) for comparing the populations is:\[ Z = \frac{\hat{p}_1 - \hat{p}_2}{SE} \]. Evaluate this expression using the sample proportions and the standard error calculated in previous steps.
06

Determine the Critical Value and Make a Decision

For a one-tailed test at \( \alpha = 0.05 \), the critical Z-value is 1.645. Compare the calculated test statistic to this critical value. If the test statistic exceeds 1.645, we reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
In hypothesis testing involving proportions, we examine the ratio of a specific characteristic within a population. For instance, in this problem, we aim to find out if conservative voters have a higher proportion of preference for paintings with fully clothed figures in comparison to liberal voters.

A proportion is denoted as \( p \), which represents the number of favorable outcomes divided by the total number of observations.
  • For conservative voters: \( \hat{p}_1 = \frac{r_1}{n_1} = \frac{45}{59} \)
  • For liberal voters: \( \hat{p}_2 = \frac{r_2}{n_2} = \frac{36}{62} \)
The "hat" symbol indicates an estimate from the sample, as opposed to the true unknown population proportion. Understanding these sample proportions is crucial for proceeding with the hypothesis test. These sample proportions summarize our sample data and help us move forward in testing whether there's a significant difference based on the hypothesis set.
Standard Error
The standard error (SE) provides a measure of the variability or "spread" of a sample statistic. It is critical in hypothesis testing, as it allows us to gauge how much the sample proportion differs from the true population proportion.

Specifically, in this problem, the standard error helps us understand the variability in the difference between two sample proportions. The calculation of SE for two proportions is given by the formula: \[ SE = \sqrt{ \hat{p}(1 - \hat{p}) \left(\frac{1}{n_1} + \frac{1}{n_2}\right) } \] This formula uses a pooled sample proportion \( \hat{p} \), which is a combined estimate from both groups:
  • \( \hat{p} = \frac{r_1 + r_2}{n_1 + n_2} \)
Using the pooled proportion allows us to obtain a single measure of variability when comparing two samples. The SE essentially tells us how much variability there is in our estimation of the difference between the two proportions.
Test Statistic
A test statistic is a standardized value that helps us determine whether to reject the null hypothesis. This value is computed from the sample data. For comparing two proportions, the test statistic used is the Z-score, which tells us how many standard errors the sample proportion difference is from the null hypothesis proportion difference.

The formula for the test statistic in this problem is: \[ Z = \frac{\hat{p}_1 - \hat{p}_2}{SE} \] where \( \hat{p}_1 \) and \( \hat{p}_2 \) are the sample proportions, and SE is the standard error of the difference.
  • If \( Z \) is large and positive, it suggests that \( \hat{p}_1 \) is significantly greater than \( \hat{p}_2 \).
  • If \( Z \) is negative, it suggests the opposite.
In hypothesis testing, we compare this calculated \( Z \) value to a critical value to make inferences about the population proportions.
Critical Value
A critical value in hypothesis testing is a threshold that determines whether the null hypothesis should be rejected. For a one-tailed test, such as the one in this problem where we are testing if one proportion is greater, the critical value is derived from the significance level \( \alpha \).

At a significance level of \( \alpha = 0.05 \), the critical Z-value is 1.645 for a one-tailed test. If the computed test statistic \( Z \) is greater than 1.645, we reject the null hypothesis, suggesting that the proportion of conservative voters who prefer paintings with fully clothed people is indeed higher than that of liberal voters.
  • This critical value represents the point beyond which only 5% of the distribution falls, indicating a rare event under the null hypothesis.
Thus, comparing the test statistic with the critical value helps us make a decision on whether the observed sample result could have happened by random chance or suggests a real difference in the populations.

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Most popular questions from this chapter

This problem is based on information regarding productivity in leading Silicon Valley companies (see reference in Problem 25). In large corporations, an "intimidator" is an employee who tries to stop communication, sometimes sabotages others, and, above all, likes to listen to him- or herself talk. Let \(x_{1}\) be a random variable representing productive hours per week lost by peer employees of an intimidator. \(\begin{array}{llllllll}x_{1}: & 8 & 3 & 6 & 2 & 2 & 5 & 2\end{array}\) A "stressor" is an employee with a hot temper that leads to unproductive tantrums in corporate society. Let \(x_{2}\) be a random variable representing productive hours per week lost by peer employees of a stressor. \(\begin{array}{lllllllll}x_{2}: & 3 & 3 & 10 & 7 & 6 & 2 & 5 & 8\end{array}\) i. Use a calculator with mean and standard deviation keys to verify that \(\bar{x}_{1}=4.00, s_{1}=2.38, \bar{x}_{2}=5.5\), and \(s_{2}=2.78 .\) ii. Assuming the variables \(x_{1}\) and \(x_{2}\) are independent, do the data indicate that the population mean time lost due to stressors is greater than the population mean time lost due to intimidators? Use a \(5 \%\) level of significance. (Assume the population distributions of time lost due to intimidators and time lost due to stressors are each mound-shaped and symmetric.)

A random sample of 49 measurements from a population with population standard deviation 3 had a sample mean of 10\. An independent random sample of 64 measurements from a second population with population standard deviation 4 had a sample mean of \(12 .\) Test the claim that the population means are different. Use level of significance \(0.01\). (a) What distribution does the sample test statistic follow? Explain. (b) State the hypotheses. (c) Compute \(\bar{x}_{1}-\bar{x}_{2}\) and the corresponding sample test statistic. (d) Find the \(P\) -value of the sample test statistic. (e) Conclude the test. (f) The results.

Consider a hypothesis test of difference of proportions for two independent populations. Suppose random samples produce \(r_{1}\) successes out of \(n_{1}\) trials for the first population and \(r_{2}\) successes out of \(n_{2}\) trials for the second population. What is the best pooled estimate \(\bar{p}\) for the population probability of success using \(H_{0}: p_{1}=p_{2} ?\)

The price-to-earnings (P/E) ratio is an important tool in financial work. A random sample of 14 large U.S. banks (J.P. Morgan, Bank of America, and others) gave the following \(\mathrm{P} / \mathrm{E}\) ratios (Reference: Forbes). \(\begin{array}{lllllll}24 & 16 & 22 & 14 & 12 & 13 & 17 \\ 22 & 15 & 19 & 23 & 13 & 11 & 18\end{array}\) The sample mean is \(\bar{x} \approx 17.1\). Generally speaking, a low \(\mathrm{P} / \mathrm{E}\) ratio indicates a "value" or bargain stock. A recent copy of the Wall Street Journal indicated that the \(\mathrm{P} / \mathrm{E}\) ratio of the entire \(\mathrm{S\&P} 500\) stock index is \(\mu=19\). Let \(x\) be a random variable representing the \(\mathrm{P} / \mathrm{E}\) ratio of all large U.S. bank stocks. We assume that \(x\) has a normal distribution and \(\sigma=4.5 .\) Do these data indicate that the \(\mathrm{P} / \mathrm{E}\) ratio of all U.S. bank stocks is less than \(19 ?\) Use \(\alpha=0.05\).

How much customers buy is a direct result of how much time they spend in a store. A study of average shopping times in a large national housewares store gave the following information (Source: Why We Buy: The Science of Shopping by P. Underhill): Women with female companion: \(8.3 \mathrm{~min} .\) Women with male companion: \(4.5 \mathrm{~min} .\) Suppose you want to set up a statistical test to challenge the claim that a woman with a female friend spends an average of \(8.3\) minutes shopping in such a store. (a) What would you use for the null and alternate hypotheses if you believe the average shopping time is less than \(8.3\) minutes? Is this a right-tailed, lefttailed, or two-tailed test? (b) What would you use for the null and alternate hypotheses if you believe the average shopping time is different from \(8.3\) minutes? Is this a right- tailed, left-tailed, or two-tailed test? Stores that sell mainly to women should figure out a way to engage the interest of men-perhaps comfortable seats and a big TV with sports programs! Suppose such an entertainment center was installed and you now wish to challenge the claim that a woman with a male friend spends only \(4.5\) minutes shopping in a housewares store. (c) What would you use for the null and alternate hypotheses if you believe the average shopping time is more than \(4.5\) minutes? Is this a right-tailed, lefttailed, or two-tailed test? (d) What would you use for the null and alternate hypotheses if you believe the average shopping time is different from \(4.5\) minutes? Is this a right- tailed, left-tailed, or two-tailed test?

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