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Based on information from Harper's Index, \(r_{1}=37\) people out of a random sample of \(n_{1}=100\) adult Americans who did not attend college believe in extraterrestrials. However, out of a random sample of \(n_{2}=100\) adult Americans who did attend college, \(r_{2}=47\) claim that they believe in extraterrestrials. Does this indicate that the proportion of people who attended college and who believe in extraterrestrials is higher than the proportion who did not attend college but believe in extraterrestrials? Use \(\alpha=0.01\).

Short Answer

Expert verified
Yes, the test indicates that a higher proportion of college attendees believe in extraterrestrials, at \(\alpha = 0.01\).

Step by step solution

01

Define the Hypotheses

We are conducting a hypothesis test to determine if the proportion of people who believe in extraterrestrials is higher among those who attended college compared to those who did not. Thus, we set up the null hypothesis as \(H_0: p_1 \geq p_2\) (where \(p_1\) is the proportion of non-college attendees who believe and \(p_2\) is the proportion of college attendees who believe), and the alternative hypothesis as \(H_a: p_1 < p_2\).
02

Significance Level and Sample Sizes

The significance level of the test is given as \(\alpha = 0.01\). The sample sizes are \(n_1 = 100\) for those who did not attend college and \(n_2 = 100\) for those who did.
03

Calculate Sample Proportions

Calculate the sample proportions for each group: \(\hat{p}_1 = \frac{r_1}{n_1} = \frac{37}{100} = 0.37\) for non-college attendees and \(\hat{p}_2 = \frac{r_2}{n_2} = \frac{47}{100} = 0.47\) for college attendees.
04

Compute the Pooled Proportion

Calculate the pooled sample proportion \(\hat{p}\) using the formula:\[\hat{p} = \frac{r_1 + r_2}{n_1 + n_2} = \frac{37 + 47}{100 + 100} = 0.42\]
05

Find Standard Error

Calculate the standard error (SE) of the sampling distribution of the difference between the sample proportions using the formula:\[SE = \sqrt{\hat{p}(1 - \hat{p}) \left(\frac{1}{n_1} + \frac{1}{n_2}\right)} = \sqrt{0.42 (1 - 0.42) \left(\frac{1}{100} + \frac{1}{100}\right)}\]Compute the value of SE for further calculations.
06

Calculate the Test Statistic

Using the standard error calculated, find the test statistic \(z\) using:\[z = \frac{\hat{p}_1 - \hat{p}_2}{SE} = \frac{0.37 - 0.47}{SE}\]Substitute the computed SE value to find \(z\).
07

Compare Test Statistic with Critical Value

Look up the critical value for a one-tailed test at \(\alpha = 0.01\), which is approximately \(-2.33\). Compare this with the computed \(z\). If \(z < -2.33\), we reject the null hypothesis.
08

Conclusion

Based on the test statistic and the critical value comparison, determine if there is sufficient evidence to conclude that a higher proportion of college attendees believe in extraterrestrials compared to non-attendees.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Proportion Comparison
Proportion comparison is a statistical analysis used to determine if there is a significant difference between the proportions of two groups. In the context of hypothesis testing, we compare sample proportions from different populations to draw conclusions about their respective population proportions. For instance, in our exercise, we are comparing the proportion of belief in extraterrestrials between college attendees and non-attendees.

To make this comparison:
  • First, calculate the sample proportion for each group. This is done by dividing the number of favorable outcomes by the total number of observations in each sample.
  • Next, use these sample proportions to determine if the difference observed is due to random variation or represents a true difference in the populations.
Proportion comparison is crucial in making informed decisions and finding meaningful patterns in different groups.
Significance Level in Hypothesis Testing
The significance level, often denoted by \( \alpha \), is the threshold we use to decide whether a hypothesis holds or not. It represents the probability of rejecting the null hypothesis when it is actually true, known as a Type I error. Common significance levels include 0.05, 0.01, and 0.10, with 0.01 being more stringent and reducing the chance of making an incorrect conclusion.

In our example, we use \( \alpha = 0.01 \), which means we are willing to accept a 1% risk of concluding that there is a difference in proportions when there isn’t one. A lower \( \alpha \) implies greater confidence in our test results, but it also requires more substantial evidence to reject the null hypothesis. Choosing the appropriate significance level is essential for balancing between accuracy and practicality in hypothesis testing.
The Role of Sample Size in Statistical Tests
Sample size is another critical component in hypothesis testing, as it affects the accuracy and reliability of the test results. Larger sample sizes generally provide more reliable estimates of the population parameters, leading to more powerful tests, which means they are more likely to detect a true effect if one exists.

In the given problem, both sample sizes are 100. This identical sample size simplifies the comparison and helps ensure that our calculated test statistic is well-founded. With an adequate sample size, we reduce the likelihood of Type II errors, where we might fail to reject the null hypothesis when it is false. Always remember, bigger samples give us a clearer, more accurate picture of the real-world differences we are trying to measure.
Interpreting the Test Statistic
The test statistic is a standardized value that helps us determine the statistical significance of our hypothesis test. Specifically, it quantifies how far our sample statistic is from the null hypothesis value in terms of standard error units. The formula for our test statistic in this exercise is \((z = \frac{\hat{p}_1 - \hat{p}_2}{SE})\), where \((\hat{p}_1\)) and \((\hat{p}_2\)) represent the sample proportions, and SE is the standard error.

Once calculated, compare the test statistic to critical values from the z-distribution corresponding to the chosen significance level (e.g., \(-2.33\) for \( \alpha = 0.01 \) in a one-tailed test). If the test statistic lies in the critical region, the null hypothesis is rejected; otherwise, it isn’t. Understanding and correctly interpreting the test statistic helps in making data-driven decisions, unveiling underlying truths about the populations compared.

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Most popular questions from this chapter

Prose rhythm is characterized by the occurrence of five-syllable sequences in long passages of text. This characterization may be used to assess the similarity among passages of text and sometimes the identity of authors. The following information is based on an article by D. Wishart and S. V. Leach appearing in Computer Studies of the Humamities and Verbal Behavior (Vol. 3, pp. 90-99). Syllables were categorized as long or short. On analyzing Plato's Republic, Wishart and Leach found that about \(26.1 \%\) of the five-syllable sequences are of the type in which two are short and three are long. Suppose that Greek archaeologists have found an ancient manuscript dating back to Plato's time (about \(427-347\) B.C. \() .\) A random sample of 317 five-syllable sequences from the newly discovered manuscript showed that 61 are of the type two short and three long. Do the data indicate that the population proportion of this type of five-syllable sequence is different (either way) from the text of Plato's Republic? Use \(\alpha=0.01\).

Snow avalanches can be a real problem for travelers in the western United States and Canada. A very common type of avalanche is called the slab avalanche. These have been studied extensively by David McClung, a professor of civil engineering at the University of British Columbia. Slab avalanches studied in Canada have an average thickness of \(\mu=67\) (Source: Avalanche Handbook by D. McClung and P. Schaerer). The ski patrol at Vail, Colorado, is studying slab avalanches in its region. A random sample of avalanches in spring gave the following thicknesses (in \(\mathrm{cm})\) : \(\begin{array}{llllllll}59 & 51 & 76 & 38 & 65 & 54 & 49 & 62 \\ 68 & 55 & 64 & 67 & 63 & 74 & 65 & 79\end{array}\) i. Use a calculator with mean and standard deviation keys to verify that \(\bar{x}=61.8\) and \(s=10.6 \mathrm{~cm} .\) ii. Assume the slab thickness has an approximately normal distribution. Use a \(1 \%\) level of significance to test the claim that the mean slab thickness in the Vail region is different from that in Canada.

In the article cited in Problem 21 , the results of the following experiment were reported. Form 2 of the Gates-MacGintie Reading Test was administered to both an experimental group and a control group after 6 weeks of instruction, during which the experimental group received peer tutoring and the control group did not. For the experimental group \(n_{1}=30\) children, the mean score on the vocabulary portion of the test was \(\bar{x}_{1}=368.4\), with sample standard deviation \(s_{1}=39.5 .\) The average score on the vocabulary portion of the test for the \(n_{2}=30\) subjects in the control group was \(\bar{x}_{2}=349.2\), with sample standard deviation \(s_{2}=56.6\). Use a \(1 \%\) level of significance to test the claim that the experimental group performed better than the control group.

If we reject the null hypothesis, does this mean that we have proved it to be false beyond all doubt? Explain your answer.

In a statistical test, we have a choice of a left-tailed test, a right-tailed test, or a two-tailed test. Is it the null hypothesis or the alternate hypothesis that determines which type of test is used? Explain your answer.

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