/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Consider a binomial experiment w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider a binomial experiment with \(n\) trials and \(f\) successes. For a test for a proportion \(p\), what is the formula for the sample test statistic? Describe each symbol used in the formula.

Short Answer

Expert verified
The test statistic is calculated using the formula \( z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}} \).

Step by step solution

01

Understand the Context

In a binomial experiment, we perform a fixed number of trials, denoted as \( n \), and count the number of successes, \( f \). We are conducting a test for a proportion, which involves comparing observed data from these trials to an expected proportion \( p \).
02

Formula for Sample Test Statistic

For a test of a proportion, the sample test statistic usually used is the \( z \)-score. This is calculated using the formula: \[ z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}} \] where \( \hat{p} \) is the sample proportion of successes, \( p \) is the hypothesized population proportion, and \( n \) is the total number of trials.
03

Define Each Symbol

- \( \hat{p} = \frac{f}{n} \): This is the sample proportion, calculated as the number of successes \( f \) divided by the number of trials \( n \).- \( p \): This is the hypothesized proportion of successes in the population.- \( n \): This is the total number of trials in the binomial experiment.- \( f \): This is the number of successes observed in the \( n \) trials.- \( z \): This is the test statistic that follows a standard normal distribution if the null hypothesis is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Test
A proportion test is a statistical test used to determine if the proportion of successes in a sample is significantly different from a hypothesized proportion in a population. In the context of a binomial experiment, where there is a fixed number of trials or observations, we often want to compare the observed proportion of successes to an expected proportion. This makes proportion tests incredibly useful in many fields such as medicine, marketing, and quality control.
When you perform a proportion test, you:
  • Start by defining the null hypothesis, often stating that there is no difference between the observed and expected proportions.
  • Then, compare the observed data against the hypothesized condition to see if the results are significant.
  • The outcome helps in deciding whether you should reject or fail to reject the null hypothesis.
These tests are a part of inferential statistics, where conclusions about a population are drawn from a sample.
Sample Test Statistic
The sample test statistic is a crucial element in statistical hypothesis testing because it quantifies how far our sample data is from the null hypothesis. For a proportion test, the sample test statistic commonly used is the z-score. This tells us how many standard deviations a sample proportion (\(\hat{p}\)) is from the hypothesized population proportion (\(p\)).
Here’s the formula for the z-score used in proportion tests:\[ z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}} \]In this formula:
  • \(\hat{p}\) represents the sample proportion and is calculated by dividing the number of successes \(f\) by the total number of trials \(n\).
  • \(p\) is the hypothesized proportion expected in the population.
  • \(n\) is the total number of trials or observations conducted in the binomial experiment.
The z-score follows the standard normal distribution under the null hypothesis. If the z-score is significantly high or low, it may prompt you to reject the null hypothesis. Understanding and calculating this statistic properly is key to making informed decisions in hypothesis testing.
Normal Distribution
Normal distribution, also known as the Gaussian distribution, is a continuous probability distribution characterized by its symmetric bell-shaped curve. It's one of the most important concepts in statistics and is often utilized in various statistical methods, including hypothesis testing.
For proportion tests, especially in large samples, the central limit theorem allows us to use the normal distribution to approximate the distribution of the sample proportion. This approximation holds when the number of trials \(n\) is large, and both the expected number of successes \(np\) and failures \(n(1-p)\) are greater than 5, ensuring the sample size is adequate for the approximation.
  • The mean of a normal distribution for a proportion test is the population proportion \(p\).
  • The standard error, which measures the dispersion of sample proportion, is given by \(\sqrt{\frac{p(1-p)}{n}}\).
When performing a proportion test, and your z-score falls within the critical region of the standard normal distribution, it suggests the observed sample proportion significantly differs from the hypothesized population proportion. Using normal distribution in this manner helps determine the probability that the observed results occurred under the null hypothesis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A random sample has 49 values. The sample mean is \(8.5\) and the sample standard deviation is \(1.5 .\) Use a level of significance of \(0.01\) to conduct a left-tailed test of the claim that the population mean is \(9.2\). (a) Is it appropriate to use a Student's \(t\) distribution? Explain. How many degrees of freedom do we use? (b) What are the hypotheses? (c) Compute the sample test statistic \(t\). (d) Estimate the \(P\) -value for the test. (e) Do we reject or fail to reject \(H_{0}\) ? (f) The results.

Suppose the \(P\) -value in a two-tailed test is \(0.0134\). Based on the same population, sample, and null hypothesis, and assuming the test statistic \(z\) is negative, what is the \(P\) -value for a corresponding left-tailed test?

The price-to-earnings (P/E) ratio is an important tool in financial work. A random sample of 14 large U.S. banks (J.P. Morgan, Bank of America, and others) gave the following \(\mathrm{P} / \mathrm{E}\) ratios (Reference: Forbes). \(\begin{array}{lllllll}24 & 16 & 22 & 14 & 12 & 13 & 17 \\ 22 & 15 & 19 & 23 & 13 & 11 & 18\end{array}\) The sample mean is \(\bar{x} \approx 17.1\). Generally speaking, a low \(\mathrm{P} / \mathrm{E}\) ratio indicates a "value" or bargain stock. A recent copy of the Wall Street Journal indicated that the \(\mathrm{P} / \mathrm{E}\) ratio of the entire \(\mathrm{S\&P} 500\) stock index is \(\mu=19\). Let \(x\) be a random variable representing the \(\mathrm{P} / \mathrm{E}\) ratio of all large U.S. bank stocks. We assume that \(x\) has a normal distribution and \(\sigma=4.5 .\) Do these data indicate that the \(\mathrm{P} / \mathrm{E}\) ratio of all U.S. bank stocks is less than \(19 ?\) Use \(\alpha=0.05\).

USA Today reported that about \(47 \%\) of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1006 Chevrolet owners and found that 490 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than \(47 \%\) ? Use \(\alpha=0.01\).

Nationally, about \(11 \%\) of the total U.S. wheat crop is destroyed each year by hail (Reference: Agricultural Statistics, U.S. Department of Agriculture). An insurance company is studying wheat hail damage claims in Weld County, Colorado. A random sample of 16 claims in Weld County gave the following data (\% wheat crop lost to hail). \(\begin{array}{rrrrrrrr}15 & 8 & 9 & 11 & 12 & 20 & 14 & 11 \\ 7 & 10 & 24 & 20 & 13 & 9 & 12 & 5\end{array}\) The sample mean is \(\bar{x}=12.5 \%\). Let \(x\) be a random variable that represents the percentage of wheat crop in Weld County lost to hail. Assume that \(x\) has a normal distribution and \(\sigma=5.0 \%\). Do these data indicate that the percentage of wheat crop lost to hail in Weld County is different (either way) from the national mean of \(11 \% ?\) U?e \(\alpha=0.01\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.