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Attitudes Refer to Exercises 4 and 10 . What conclusion would you make at the =0.05 level?

Short Answer

Expert verified

There is convincing evidence to help the claim that older students have better attitudes toward school, on average.

Step by step solution

01

Step 1:Given information

=0.05level

02

Step 2:Explaination

P=0.0101

=0.05

Given claim is mean is better than 115

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis statement is that the population proportion is equal to the value given in the claim. If the null hypothesis is the claim, then the alternative hypothesis statement is the opposite of the null hypothesis.

H0:=115

H1:>115

If the P-value is smaller than the significance level , then reject the null hypothesis:

0.1265>0.05Fail to rejectH0

There is not enough convincing evidence to help the claim that less than 75%of the students at researcher's school finished their homework last night.

0.0101<0.05RejectH0

There is convincing evidence to help the claim that older students have better attitudes toward school, on average.

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Most popular questions from this chapter

The standardized test statistic for a test of H0:p=0.4versus Ha:pnotequalto0.4isz=2.43This test is

a. not significant at either =0.05or =0.01

b. significant at =0.05but not at=0.01

c. significant at=0.01but not at =0.05

d. significant at both =0.05and=0.01

e. inconclusive because we don鈥檛 know the value of p^

A company that manufactures classroom chairs for high school students

claims that the mean breaking strength of the chairs is 300 pounds. One of the chairs collapsed beneath a 220-pound student last week. You suspect that the manufacturer is exaggerating the breaking strength of the chairs, so you would like to perform a test of H0:=300Ha:<300where 渭 is the true mean breaking strength of this company鈥檚 classroom chairs.

a. The power of the test to detect that 渭=294 based on a random sample of 30

chairs and a significance level of 伪=0.05 is 0.71. Interpret this value.

b. Find the probability of a Type I error and the probability of a Type II error for the test in part (a).

c. Describe two ways to increase the power of the test in part (a).

Walking to school A recent report claimed that 13%of students typically walk to school. DeAnna thinks that the proportion is higher than 0.13at her large elementary school. She surveys a random sample of 100students and finds that 17typically walk to school. DeAnna would like to carry out a test at the =0.05significance level of H0:p=0.13versus Ha:p>0.13, where p= the true proportion of all students at her elementary school who typically walk to school. Check if the conditions for performing the significance test are met.

Walking to school Refer to Exercise 36.

a. Explain why the sample result gives some evidence for the alternative hypothesis.

b. Calculate the standardized test statistic and P-value.

c. What conclusion would you make?

We want to be rich In a recent year, 73%of first-year college students responding to a national survey identified 鈥渂eing very well-off financially鈥 as an important personal goal. A state university finds that 132of an SRS of 200of its first-year students say that this goal is important. Is there convincing evidence at the =0.05significance level that the proportion of all first-year students at this university who think being very well-off is important differs from the national value of 73%?

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