91Ó°ÊÓ

$\mathrm{Î\pm }=0.10\mathrm{Î\pm }=0.10$

$P=0.0589$

$\mathrm{Î\pm }=0.10$

$\text{Given claim is mean is}180$

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis statement is that the population proportion is equal to the value given in the claim. If the null hypothesis is the claim, then the alternative hypothesis statement is the opposite of the null hypothesis.

$H_0:\mathrm{μ}=180$

$H_1:\mathrm{μ}≠180$

If the $P$-value is smaller than the significance level $\mathrm{Î\pm }$, then reject the null hypothesis:

$0.0589<0.10⇒\text{Reject}{H}_0$

There is sufficient convincing evidence that the correct mean volume of liquid is different from $180$millilitres.

A$5\%$ significance level was used

$P=0.0589$

$\mathrm{Î\pm }=0.10$

$\text{Given claim of mean is}180.$

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis statement is that the population proportion is equal to the value given in the claim. If the null hypothesis is the claim, then the alternative hypothesis statement is the opposite of the null hypothesis.

$H_0:\mathrm{μ}=180$

$H_1:\mathrm{μ}≠180$

If the $P$-value is smaller than the significance level , then reject the null hypothesis:

$0.0589<0.10⇒Reject{H}_0$

There is enough convincing evidence that the true mean volume of liquid is different from $180$millilitres. It is observed that the conclusion changed.