/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 9. Munching Froot Loops Kellogg鈥檚... [FREE SOLUTION] | 91影视

91影视

Munching Froot Loops Kellogg鈥檚 Froot Loops cereal comes in six colors:

orange, yellow, purple, red, blue, and green. Charise randomly selected 120 loops and noted the color of each. Here are her data:

Do these data provide convincing evidence at the 5% significance level that Kellogg鈥檚 Froot Loops do not contain an equal proportion of each color?

Short Answer

Expert verified

There is insufficient evidence to refute Kellogg's assertion that its Froot Loop includes an equal quantity of each flavor.

Step by step solution

01

Given information

Significance level: 5% = 0.05

02

Concept

Null hypothesis: H0

When the value of P is less than or equal to the significance level, the null hypothesis is rejected.

03

Explanation

The Pvalue is used to calculate the likelihood of a test statistic or a more extreme number.

The P-value in the appendix, which contains the X2value in the row df=5may be found in the chi-square distribution table.

0.15<P<0.20

When the value of Pis not less than or equal to the significance level, the null hypothesis is not rejected.

P>0.05: fail to reject H0

Hence, There is insufficient evidence to disprove the company's assertion that Kellogg's produces Froot Loop.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies associated with household current are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who had died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either a high-current configuration (HCC) or a low-current configuration (LCC). Here are the data:

Computer software was used to analyze the data. The output included the value X2=0.435

Which of the following may we conclude, based on the chi-square test results?

a. There is convincing evidence of an association between wiring configuration and the chance that a child will develop some form of cancer.

b. HCC either causes cancer directly or is a major contributing factor to the development of cancer in children.

c. Leukemia is the most common type of cancer among children.

d. There is not convincing evidence of an association between wiring configuration and the type of cancer that caused the deaths of children.

e. There is convincing evidence that HCC does not cause cancer in children.

Gummy bears Courtney and Lexi wondered if the distribution of color was

the same for name-brand gummy bears (Haribo Gold) and store-brand gummy bears

(Great Value). To investigate, they randomly selected bags of each type and counted the

number of gummy bears of each color.

Do these data provide convincing evidence that the distributions of color differ for name-

brand gummy bears and store-brand gummy bears?

Here are the data:

Fruit flies Biologists wish to mate pairs of fruit flies having genetic makeup RrCc, indicating that each has one dominant gene (R) and one recessive gene (r) for eye color, along with one dominant (C) and one recessive (c) gene for wing type. Each offspring will receive one gene for each of the two traits from each parent, so the biologists predict that the following phenotypes should occur in a ratio of 9:3:3:1:

Assume that the conditions for inference are met. Carry out a test at the =0.05 significance level of the proposed genetic model.

鈥淲ill changing the rating scale on a survey affect how people answer the question?鈥 To find out, the group took an SRS of 50students from an alphabetical roster of the school鈥檚 just over 1000students. The first 22students chosen were asked to rate the cafeteria food on a scale of 1(terrible) to 5(excellent). The remaining 28students were asked to rate the cafeteria food on a scale of 0(terrible) to 4(excellent). Here are the data:

The students decided to compare the average ratings of the cafeteria food on the two scales.

a. Find the mean and standard deviation of the ratings for the students who were given the 1to5scale.

b. For the students who were given the 0to4scale, the ratings have a mean of 3.21and a standard deviation of 0.568. Since the scales differ by one point, the group decided to add 1to each of these ratings. What are the mean and standard deviation of the adjusted ratings?

c. Would it be appropriate to compare the means from parts (a) and (b) using a two-sample t test? Justify your answer

Aw, nuts! A company claims that each batch of its deluxe mixed nuts

contains 52% cashews, 27%almonds, 13% macadamia nuts, and 8% Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table displays the sample data.

a. State appropriate hypotheses for performing a test of the company鈥檚 claim.

b. Calculate the expected count for each type of nut.

c. Calculate the value of the chi-square test statistic.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.