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Aw, nuts! Refer to Exercise 1.

a. Confirm that the expected counts are large enough to use a chi-square distribution to calculate the P-value. What degrees of freedom should you use?

b. Use Table C to find the P-value. Then use your calculator鈥檚 蠂2 cdf command.

c. What conclusion would you draw about the company鈥檚 claimed distribution for its deluxe mixed nuts?

Short Answer

Expert verified

Part (a) The df=3

Part (b) P-value =0.0858

Part (c) There isn't enough evidence to refute the claim concerning the probability distribution in question.

Step by step solution

01

Part (a) Step 1: Given information

Type of countCountFrequencyExpected
Cashew8352%78
Almond2927%40.5
Macadamia2013%19.5
Brazil188%12
Total150100%150

Chi square test statistic=6.60

02

Part (a) Step 2: Calculation

The projected counts are large enough to use a chi-square distribution if all predicted counts are at least 5This condition is satisfied.

The degrees of freedom =df=c-1=4-1=3

03

Part (b) Step 1: Given information

The degrees of freedom =df=3

04

Part (b) Step 2: Calculation

The p-value using table for df=3 is,

0.05<P<0.10

The excel formula, =CHIDIST(6.6,3)

P-value=0.0858

05

Part (c) Step 1: Calculation

Chi square test statistic=6.60

The degrees of freedom=df=c-1=4-1=3

P-value=0.0858

Here, p-value>0.05fail to reject H0

There isn't enough evidence to refute the claim concerning the probability distribution in question.

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