/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 35. Here are the weights (in milligr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Here are the weights (in milligrams) of 58 diamonds from a nodule

carried up to the earth’s surface in surrounding rock. These data represent a population of diamonds formed in a single event deep in the earth.

Make a histogram to display the distribution of weight. Describe the distribution.

Short Answer

Expert verified

The distribution is skewed to right, spread from 0 to 35 with center at 2.5 and without outliers.

Step by step solution

01

Given information

Data illustrating the population of diamonds generated in a single deep-earth event:

02

Calculation

Frequency table:

Calculate the frequency of each interval, which is the number of data values that fall within it.

The first value of the first interval is 0 having a width of 5

Thus,

The first interval is 0−<5

The interval follows

5−<10,10−<15 etc.

The intervals will be established until all of the data values are assigned to exactly one interval.

Frequency Histogram:

Interval bounds must be used to define the bars, and each bar's width must be the same.

Whereas, the height needs to be equal to the frequency.

Spread: In the data set, the weight appears to range from 0.1 to 33.8 and in the histogram, it appears to range from 0 to 35

Shape: The highest bars are on the left of the histogram, with a tail of smaller balls to the right. As a result, the shape will be slanted toward the right.

Outliers: There are no outliers because the histogram has no gaps.

Because it is in the middle of the highest bar, the distribution's center looks to be around 2.5

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In addition to the regression line, the report on the Mumbai measurements says that r2 =0.95. This suggests that

a. although arm span and height are correlated, arm span does not predict height very accurately.

b. height increases by 0.95=0.97 cm for each additional centimeter of arm

span.

c. 95% of the relationship between height and arm span is accounted for by the regression line.

d. 95% of the variation in height is accounted for by the regression line with x = arm span. e. 95% of the height measurements are accounted for by the regression line with x = arm span.

Long strides The scatterplot shows the relationship between x = height of a student (in inches) and y = number of steps required to walk the length of a school hallway, along with the regression line y^=113.6−0.921x

a. Calculate and interpret the residual for Kiana, who is 67 inches tall and took 49 steps to walk the hallway.

b. Matthew is 10 inches taller than Samantha. About how many fewer steps do you expect Matthew to take compared to Samantha?

Who’s got hops? Haley, Jeff, and Nathan measured the height (in inches)

and vertical jump (in inches) of 74 students at their school.34 Here is a scatterplot of the data, along with the least-squares regression line. Jacob (highlighted in red) had a vertical jump of nearly 3 feet!

a. Describe the influence that Jacob’s point has on the equation of the least-squares regression line.

b. Describe the influence that Jacob’s point has on the standard deviation of the residuals and r2

Calculating achievement a study found a strong link between the number of calculators possessed by high school pupils and their arithmetic proficiency, according to the principle of a high school. Based on this study, he decides to buy each student at his school two calculators, hoping to improve their math achievement. Explain the flaw in the principal’s reasoning.

Suppose that the measurements of arm span and height were converted from centimeters to meters by dividing each measurement by 100. How will this conversion affect the values of r2 and s?

a. r2 will increase, s will increase.

b. r2 will increase, s will stay the same.

c. r2 will increase, s will decrease.

d. r2 will stay the same, s will stay the same.

e. r2 will stay the same, s will decrease.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.