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A quality control inspector will measure the salt content (in milligrams) in a random sample of bags of potato chips from an hour of production. Which of the following would result in the smallest margin of error in estimating the mean salt content \(\mu ?\) (a) \(90 \%\) confidence; \(n=25\) (b) \(90 \%\) confidence; \(n=50\) (c) \(95 \%\) confidence; \(n=25\) (d) \(95 \%\) confidence; \(n=50\) (e) \(n=100\) at any confidence level

Short Answer

Expert verified
Option (e), \( n=100 \), results in the smallest margin of error.

Step by step solution

01

Understanding Margin of Error

The margin of error in a confidence interval is given by the formula: \( ME = z^* \cdot \frac{\sigma}{\sqrt{n}} \), where \( z^* \) is the critical value from the z-distribution, \( \sigma \) is the standard deviation, and \( n \) is the sample size. To minimize the margin of error, we can either increase the sample size \( n \) or use a lower confidence level (which has a smaller \( z^* \)).
02

Comparing Sample Sizes

Increasing the sample size \( n \) decreases the margin of error since \( ME \) is inversely proportional to \( \sqrt{n} \). Options (b), (d), and (e) show larger sample sizes than (a) and (c). Among these, option (e) with \( n=100 \) provides the smallest margin of error.
03

Comparing Confidence Levels

The smaller the confidence level, the smaller the \( z^* \) value, thus the smaller the margin of error. A \( 90\% \) confidence level (options (a) and (b)) has a smaller \( z^* \) than a \( 95\% \) confidence level (options (c) and (d)), which reduces the margin of error.
04

Selecting the Smallest Margin of Error

Option (e) has the highest sample size \( n=100 \), irrespective of confidence level, which generally results in the smallest margin of error compared to lower sample sizes. Even if the confidence level is higher, the impact of the large sample size outweighs it. Therefore, option (e) will typically provide the smallest margin of error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
The confidence level in statistics refers to the degree of certainty that a parameter lies within the specified confidence interval. It is usually expressed as a percentage, such as 90% or 95%. The confidence level indicates how often you expect the true parameter to fall within this interval if you were to take many samples.

A higher confidence level means that you're more certain about the interval containing the true mean, but it also comes with a larger margin of error. This is because the critical value, which is based on the confidence level, increases. Thus, making the interval wider

In practical terms, when comparing confidence levels:
  • 90% Confidence Level implies less certainty but a smaller critical value.
  • 95% Confidence Level implies more certainty but a larger critical value.
Choosing the appropriate confidence level depends on how confident you want to be in your interval estimate versus how wide you can tolerate the interval.
Sample Size
Sample size, denoted as "n", plays a crucial role in determining the margin of error. The sample size refers to the number of observations or data points used in a statistical sample.

When it comes to reducing the margin of error, a larger sample size typically helps. This is because the margin of error is inversely proportional to the square root of the sample size. As the sample size increases, the square root of the sample size also increases, causing the margin of error to decrease.

Here’s how it works in practice:
  • Smaller Sample Size (e.g., n=25) results in a larger margin of error, since there is less data to base the estimate on.
  • Larger Sample Size (e.g., n=100) results in a smaller margin of error, giving a more precise estimate of the population parameter.
Larger sample sizes enhance precision, but they also require more resources and time to collect data.
Critical Value
The critical value, often represented as "z*" or "t*", is a factor used to calculate the margin of error in a confidence interval. It is determined from statistical tables, such as the standard normal distribution for z or t-distribution tables.

The critical value depends on the chosen confidence level. Here’s a simple breakdown:
  • A higher confidence level (like 95%) leads to a higher critical value, since the interval needs to be wider to ensure higher certainty.
  • A lower confidence level (like 90%) results in a smaller critical value, leading to a narrower interval and less certainty.
Essentially, the critical value balances the width of the confidence interval and the degree of certainty that the interval truly includes the population parameter. For precise estimation, choosing the right confidence level and thereby the critical value is crucial.
Standard Deviation
Standard deviation, denoted \( \sigma \), measures the amount of variation or dispersion in a set of data points. It's a key input in the formula for margin of error, as it indicates how much the values in a sample differ from the mean of that sample.

In the context of estimating means, a smaller standard deviation implies that data points are closely clustered around the mean, while a larger standard deviation indicates more spread out data.

Here's how it impacts margin of error:
  • Smaller Standard Deviation reduces margin of error because the data is more consistent.
  • Larger Standard Deviation increases the margin of error due to greater variability in data.
Understanding standard deviation helps in choosing samples and planning experiments, as consistent data leads to more reliable estimates.

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Most popular questions from this chapter

In a recent National Survey of Drug Use and Health, 2312 of 5914 randomly selected full-time U.S. college students were classified as binge drinkers. \({ }^{13}\) (a) Calculate and interpret a \(99 \%\) confidence interval for the population proportion \(p\) that are binge drinkers. (b) A newspaper article claims that \(45 \%\) of full-time U.S. college students are binge drinkers. Use your result from part (a) to comment on this claim.

Check whether each of the conditions is met for calculating a confidence interval for the population proportion \(\bar{p}\). The small round holes you often see in sea shells were drilled by other sea creatures, who ate the former dwellers of the shells. Whelks often drill into mussels, but this behavior appears to be more or less common in different locations. Researchers collected whelk eggs from the coast of Oregon, raised the whelks in the laboratory, then put each whelk in a container with some delicious mussels. Only 9 of 98 whelks drilled into a mussel. \({ }^{11}\) The researchers want to estimate the proportion \(p\) of Oregon whelks that will spontaneously drill into mussels.

A bunion on the big toe is fairly uncommon in youth and often requires surgery. Doctors used X-rays to measure the angle (in degrees) of deformity on the big toe in a random sample of 37 patients under the age of 21 who came to a medical center for surgery to correct a bunion. The angle is a measure of the seriousness of the deformity. For these 37 patients, the mean angle of deformity was 24.76 degrees and the standard deviation was 6.34 degrees. A dotplot of the data revealed no outliers or strong skewness. \({ }^{26}\) (a) Construct and interpret a \(90 \%\) confidence interval for the mean angle of deformity in the population of all such patients. (b) Researchers omitted one patient with a deformity angle of 50 degrees from the analysis due to a measurement issue. What effect would including this outlier have on the confidence interval in part (a)? Justify your answer without doing any calculations.

Stores advertise price reductions to attract customers. What type of price cut is most attractive? Experiments with more than one factor allow insight into interactions between the factors. A study of the attractiveness of advertised price discounts had two factors: percent of all foods on sale \((25 \%, 50 \%, 75 \%,\) or \(100 \%)\) and whether the discount was stated precisely (as in, for example, "60\% off") or as a range (as in "40\% to \(70 \%\) off"). Subjects rated the attractiveness of the sale on a scale of 1 to 7 . (a) Describe a completely randomized design using 200 student subjects. (b) Explain how you would use the partial table of random digits below to assign subjects to treatment groups. Then use your method to select the first 3 subjects for one of the treatment groups. Show your work clearly on your paper. $$\begin{array}{llllllll}45740 & 41807 & 65561 & 33302 & 07051 & 93623 & 18132 & 09547 \\\12975 & 13258 & 13048 & 45144 & 72321 & 81940 & 00360 & 02428\end{array}$$ (c) The figure below shows the mean ratings for the eight treatments formed from the two factors. \({ }^{32}\) Based on these results, write a careful description of how percent on sale and precise discount versus range of discounts influence the attractiveness of a sale.

A $$ 95 \%$$ confidence interval for the mean body mass index (BMI) of young American women is \(26.8 \pm 0.6\). Discuss whether each of the following explanations is correct. (a) We are confident that \(95 \%\) of all young women have BMI between 26.2 and 27.4 . (b) We are \(95 \%\) confident that future samples of young women will have mean BMI between 26.2 and 27.4 . (c) Any value from 26.2 to 27.4 is believable as the true mean BMI of young American women. (d) If we take many samples, the population mean BMI will be between 26.2 and 27.4 in about \(95 \%\) of those samples. (e) The mean BMI of young American women cannot be 28 .

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