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Decreasing the sample size from 750 to 375 would multiply the standard deviation by (a) 2 . (c) \(1 / 2\). (e) none of these. (b) \(\sqrt{2}\). (d) \(1 / \sqrt{2}\).

Short Answer

Expert verified
The standard deviation is multiplied by \( \sqrt{2} \), option (b).

Step by step solution

01

Understand the Relationship

The standard deviation of the sample mean, often called the standard error, is related to the sample size. Specifically, the standard error is equal to the population standard deviation divided by the square root of the sample size: \( SE = \frac{\sigma}{\sqrt{n}} \).
02

Initial and Final Standard Deviation Calculation

Originally, the sample size is 750, so the initial standard error is \( SE_1 = \frac{\sigma}{\sqrt{750}} \). After reducing the sample size to 375, the new standard error is \( SE_2 = \frac{\sigma}{\sqrt{375}} \).
03

Determine the Factor of Increase

To find how much the standard deviation is multiplied, calculate the ratio \( \frac{SE_2}{SE_1} \):\[ \frac{SE_2}{SE_1} = \frac{\frac{\sigma}{\sqrt{375}}}{\frac{\sigma}{\sqrt{750}}} = \frac{\sqrt{750}}{\sqrt{375}} \]
04

Simplify the Ratio

Simplify \( \frac{\sqrt{750}}{\sqrt{375}} \):\[ \frac{\sqrt{750}}{\sqrt{375}} = \sqrt{\frac{750}{375}} = \sqrt{2} \].
05

Match the Result to Options

The result \( \sqrt{2} \) corresponds to option (b). This means the standard deviation is multiplied by \( \sqrt{2} \) when the sample size is decreased from 750 to 375.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
The concept of sample size is crucial in statistics. A sample size refers to the number of individual data points or observations taken from a larger population for analysis. In research, an adequate sample size is important because it ensures that the results of your analysis are representative of the whole population. When the sample size is large, it increases the reliability and validity of the statistical results.

However, changing the sample size directly impacts the standard error. The standard error is inversely related to the square root of the sample size. This relationship is expressed in the formula: \[ SE = \frac{\sigma}{\sqrt{n}} \]where:
  • \( SE \) is the standard error,
  • \( \sigma \) is the population standard deviation, and
  • \( n \) is the sample size.
Reducing the sample size will increase the standard error and decrease the precision of the estimates derived from your sample.
Population Standard Deviation
Population standard deviation, often represented by the Greek letter \( \sigma \), measures the dispersion of a set of data points in relation to the mean for the entire population. It's a fundamental concept in statistics that tells us how much individual data points, as a whole, differ from the population mean.
  • A low population standard deviation indicates that the data points tend to be close to the mean.
  • A high population standard deviation signifies that the data points are spread out over a wider range of values.
In many statistical formulas, the population standard deviation plays a critical role, such as when calculating the standard error. Understanding and accurately measuring the population standard deviation helps in making sound predictions and assessments of data variability across the population.
Square Root Calculation
Square root calculations are fundamental in many statistical analyses, particularly when dealing with the standard error. The square root operation transforms a number by finding a value that, when multiplied by itself, results in the original number. This is represented mathematically as \( \sqrt{n} \).

In the context of standard error and our problem, the square root is essential in deriving the standard error from the population standard deviation and the sample size. If you decrease the sample size, the effect is partially mitigated by the square root operation, which is seen in our standard error formula. When calculating the factor of increase in standard deviation, as in our example, manipulating the square roots (such as \( \sqrt{750} \) and \( \sqrt{375} \)) was critical in finding that the factor is \( \sqrt{2} \). The clever handling of square roots allows for simplifying complex ratios and understanding the impact of sample size on standard deviation.

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Most popular questions from this chapter

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