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Songs on an iPod David's iPod has about 10,000 songs. The distribution of the play times for these songs is heavily skewed to the right with a mean of 225 seconds and a standard deviation of 60 seconds. Suppose we choose an SRS of 10 songs from this population and calculate the mean play time \(\bar{x}\) of these songs. What are the mean and the standard deviation of the sampling distribution of \(\bar{x}\) ? Explain.

Short Answer

Expert verified
Mean: 225 seconds, Standard Deviation: 18.97 seconds

Step by step solution

01

Identify Mean of Population

The mean of the population, denoted as \( \mu \), is given as 225 seconds. In a sampling distribution of sample means, the mean \( \mu_{\bar{x}} \) is equal to the population mean \( \mu \). Therefore, \( \mu_{\bar{x}} = 225 \) seconds.
02

Calculate Standard Deviation of Sample Means

The formula to calculate the standard deviation of the sampling distribution of sample means, also known as the standard error, is given by \( \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the standard deviation of the population (60 seconds), and \( n \) is the sample size (10 songs).
03

Plug Values into Formula

Substitute the known values into the standard error formula: \( \sigma_{\bar{x}} = \frac{60}{\sqrt{10}} \).
04

Compute the Standard Error

Calculate the value: \( \sigma_{\bar{x}} = \frac{60}{\sqrt{10}} \approx 18.97 \). The standard deviation of the sampling distribution of \( \bar{x} \) is approximately 18.97 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Population
The mean of a population is a central concept in statistics referring to the average of all values in a population. It's denoted by the Greek letter \( \mu \). In David's iPod example, the population mean of the song play times is given as 225 seconds. This means if you sum up all play times of the 10,000 songs and then divide by 10,000, you would get 225 seconds.

Since we're dealing with a sampling distribution of sample means, an important feature is that the mean of the sampling distribution (denoted by \( \mu_{\bar{x}} \)) equals the mean of the population. Therefore, no matter how many samples you take or their size, the average of their means will hover around 225 seconds.
Standard Deviation of Sample Means
The standard deviation of sample means gives us a sense of how much variability there is from one sample mean to another. It's important to understand that this is different from the standard deviation of the population itself.

In our example, the standard deviation of sample means is calculated using the formula \( \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \). Here, \( \sigma \) is the standard deviation of the population, which is 60 seconds, and \( n \) is the sample size, 10 songs in this case. By plugging the numbers into the formula, we calculate \( \sigma_{\bar{x}} \approx 18.97 \) seconds.

This means that the average play time of different samples of 10 songs can vary by approximately 18.97 seconds around the population mean of 225 seconds.
Standard Error
Standard error is a critical concept in statistics, helping us understand how much sample means are expected to deviate from the actual population mean. It's the standard deviation of the sampling distribution of sample means.

For David's iPod songs, the standard error was calculated to be approximately 18.97 seconds. This tells us that if you repeatedly took samples of 10 songs and calculated their means, the distribution of those sample means would have a spread or standard deviation of about 18.97 seconds.

This measure is particularly helpful in estimating population parameters. A smaller standard error implies that the sample mean is a more accurate reflection of the population mean, giving more confidence in statistical analyses.
Simple Random Sample
A simple random sample (SRS) is a fundamental statistical concept, ensuring every member of a population has an equal chance of being included in a sample. This method is crucial for obtaining unbiased results.

In the context of David's iPod, selecting an SRS of 10 songs from his entire collection of 10,000 introduces randomization, which is key for accurate statistical inference. It avoids systematic bias and gives each song an equal opportunity to be chosen.

This technique supports the representativeness of the sample, making any conclusions about the sample applicable to the whole population, as long as the sample size and selection method are appropriate.

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Most popular questions from this chapter

The candy machine Suppose a large candy machine has \(15 \%\) orange candies. Imagine taking an SRS of 25 candies from the machine and observing the sample proportion \(\hat{p}\) of orange candies. (a) What is the mean of the sampling distribution of \(\hat{p}\) ? Why? (b) Find the standard deviation of the sampling distribution of \(\hat{p}\). Check to see if the \(10 \%\) condition is met. (c) Is the sampling distribution of \(\hat{p}\) approximately Normal? Check to see if the Large Counts condition is met. (d) If the sample size were 225 rather than \(25,\) how would this change the sampling distribution of \(\hat{p} ?\)

Predict the election A polling organization plans to ask a random sample of likely voters who they plan to vote for in an upcoming election. The researchers will report the sample proportion \(\hat{p}\) that favors the incumbent as an estimate of the population proportion \(p\) that favors the incumbent. Explain to someone who knows little about statistics what it means to say that \(\hat{p}\) is an unbiased estimator of \(p\).

How many people in a car? A study of rush-hour traffic in San Francisco counts the number of people in each car entering a freeway at a suburban interchange. Suppose that this count has mean 1.5 and standard deviation 0.75 in the population of all cars that enter at this interchange during rush hours. (a) Could the exact distribution of the count be Normal? Why or why not? (b) Traffic engineers estimate that the capacity of the interchange is 700 cars per hour. Find the probability that 700 randomly selected cars at this freeway entrance will carry more than 1075 people. Show your work. (Hint: Restate this event in terms of the mean number of people \(\bar{x}\) per car.

Lightning strikes The number of lightning strikes on a square kilometer of open ground in a year has mean 6 and standard deviation \(2.4 .\) The National Lightning Detection Network (NLDN) uses automatic sensors to watch for lightning in a random sample of 10 one-square-kilometer plots of land. (a) What are the mean and standard deviation of the sampling distribution of \(\bar{x}\), the sample mean number of strikes per square kilometer? (b) Explain why you cannot safely calculate the probability that \(\bar{x}<5\) based on a sample of size 10 . (c) Suppose the NLDN takes a random sample of \(n=50\) square kilometers instead. Explain how the central limit theorem allows us to find the probability that the mean number of lightning strikes per square kilometer is less than \(5 .\) Then calculate this probability. Show your work.

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