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Sharing music online (5.2) A sample survey reports that \(29 \%\) of Internet users download music files online, \(21 \%\) share music files from their computers, and \(12 \%\) both download and share music. \({ }^{5}\) Make a Venn diagram that displays this information. What percent of Internet users neither download nor share music files?

Short Answer

Expert verified
62% of Internet users neither download nor share music files.

Step by step solution

01

Define Sets

Let \( A \) represent the set of internet users who download music, and \( B \) represent the set of users who share music. We are given the following probabilities: \( P(A) = 0.29 \), \( P(B) = 0.21 \), and \( P(A \cap B) = 0.12 \).
02

Use Venn Diagram Formula to Find Union

To find \( P(A \cup B) \), the probability of either downloading or sharing music, use the formula: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.29 + 0.21 - 0.12 = 0.38 \] This is the percentage of internet users involved in downloading or sharing music.
03

Find the Complement

To determine the percentage of internet users who neither download nor share music files, calculate the complement of \( P(A \cup B) \). Using the formula: \[ P(\text{Neither}) = 1 - P(A \cup B) = 1 - 0.38 = 0.62 \]
04

Convert to Percentage

Convert \( P(\text{Neither}) = 0.62 \) to a percentage: \[ 0.62 \times 100\% = 62\% \] Thus, 62% of Internet users neither download nor share music files.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a way of expressing how likely an event is to occur. It ranges from 0 to 1, where 0 means the event will not occur and 1 means it certainly will happen. In real-world terms, we use percentages to convey probability. For example, if the probability of rain is 0.3, that means there is a 30% chance of rain.

In our exercise, we deal with probabilities of different events, like downloading or sharing music files. For instance, the probability of an internet user downloading music is 0.29 or 29%. Calculations often involve combining or comparing probabilities.

Understanding probability helps you quantify the level of certainty about predictions and assumptions you make. Being able to calculate probabilities is useful in areas ranging from business to science and technology.
Complement Rule
The Complement Rule is a fundamental principle in probability. It helps find the probability that an event does not occur by subtracting the probability of the event from 1. This rule is based on the idea that the total probability of all possible outcomes equals 1.

In the context of our exercise, we use the Complement Rule to calculate the probability of users neither downloading nor sharing music. First, we find the probability of users who do either, and then apply the Complement Rule: subtract the found probability from 1. This gives the probability that an event's "complement" happens — in this case, not downloading nor sharing music.
  • Probability of downloading or sharing: 38% (0.38)
  • Probability of neither: 100% - 38% = 62% (0.62)
Using this rule simplifies problems considerably by showing that tracking what doesn't happen can be easier than focusing on what does.
Set Theory
Set Theory is a branch of mathematical logic that deals with collections of objects, called sets. It is a foundational system for mathematics. It helps understand how items relate to each other and how different sets interact.

In our exercise, we define two sets: Set A and Set B. Set A includes internet users who download music files, while Set B includes those who share files. The intersection of these sets, noted as \(A \cap B\), contains users who both download and share. Knowing these relationships helps us visualize and calculate probabilities using Venn Diagrams.
  • Set \(A\): Downloaders
  • Set \(B\): Sharers
  • Intersection \(A \cap B\): Users doing both
A clear understanding of Set Theory provides a powerful framework for organizing data and solving complex problems.
Sample Survey
A sample survey is a study that gathers data from a subset of a population to make inferences about the entire group. The goal is to collect enough representative data to draw reasonable conclusions.

In the exercise example, we're given data from a survey about internet users' habits. The survey tells us how many people download or share music, as well as those who do both. Knowledge from sample surveys such as these can inform business strategies and policy-making by showing trends and habits among populations.
  • Represents a population through a sample
  • Allows informed decisions using collected data
  • Reveals trends, habits, and problem areas
Sample survey results are essential for providing insights into how a large group behaves based on a smaller, manageable dataset.

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Most popular questions from this chapter

Who owns a Harley? Harley-Davidson motorcycles make up \(14 \%\) of all the motorcycles registered in the United States. You plan to interview an SRS of 500 motorcycle owners. How likely is your sample to contain \(20 \%\) or more who own Harleys? Show your work.

Songs on an iPod David's iPod has about 10,000 songs. The distribution of the play times for these songs is heavily skewed to the right with a mean of 225 seconds and a standard deviation of 60 seconds. Suppose we choose an SRS of 10 songs from this population and calculate the mean play time \(\bar{x}\) of these songs. What are the mean and the standard deviation of the sampling distribution of \(\bar{x}\) ? Explain.

Increasing the sample size of an opinion poll will reduce the (a) bias of the estimates made from the data collected in the poll. (b) variability of the estimates made from the data collected in the poll. (c) effect of nonresponse on the poll. (d) variability of opinions in the sample. (e) variability of opinions in the population.

Bottling cola A bottling company uses a filling machine to fill plastic bottles with cola. The bottles are supposed to contain 300 milliliters \((\mathrm{ml})\). In fact, the contents vary according to a Normal distribution with mean \(\mu=298 \mathrm{ml}\) and standard deviation \(\sigma=3 \mathrm{ml}\). (a) What is the probability that a randomly selected bottle contains less than \(295 \mathrm{ml}\) ? Show your work. (b) What is the probability that the mean contents of six randomly selected bottles are less than \(295 \mathrm{ml}\) ? Show your work.

Cereal A company's cereal boxes advertise 9.65 ounces of cereal. In fact, the amount of cereal in a randomly selected box follows a Normal distribution with mean \(\mu=9.70\) ounces and standard deviation \(\sigma=0.03\) ounces. (a) What is the probability that a randomly selected box of the cereal contains less than 9.65 ounces of cereal? Show your work. (b) Now take an SRS of 5 boxes. What is the probability that the mean amount of cereal \(\bar{x}\) in these boxes is 9.65 ounces or less? Show your work.

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