/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 103 A fastfood restaurant runs a pro... [FREE SOLUTION] | 91Ó°ÊÓ

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A fastfood restaurant runs a promotion in which certain food items come with game pieces. According to the restaurant, 1 in 4 game pieces is a winner. 103\. If Jeff keeps playing until he wins a prize, what is the probability that he has to play the game exactly 5 times? (a) \((0.25)^{5}\) (b) \((0.75)^{4}\) (c) \((0.75)^{5}\) (d) \((0.75)^{4}(0.25)\) (e) \(\left(\begin{array}{l}5 \\ 1\end{array}\right)(0.75)^{4}(0.25)\)

Short Answer

Expert verified
The probability is \((0.75)^4 (0.25)\), which is option (d).

Step by step solution

01

Understanding the Problem

We need to find the probability that Jeff will win on his 5th attempt. The game piece probability of winning is 1/4, or 0.25. The probability of not winning is 3/4, or 0.75.
02

Probability for First Four Attempts

Jeff must lose the game four times before winning on the fifth attempt. The probability of losing a single game is 0.75. Thus, the probability of losing four times is \((0.75)^4\).
03

Winning on the Fifth Attempt

The probability of winning on the fifth attempt is 0.25, the probability of winning a single game.
04

Calculating the Total Probability

To find the probability that Jeff wins on the 5th attempt, multiply the probability of losing four times by the probability of winning once on the fifth attempt:\((0.75)^4 \times 0.25 \).
05

Solution

The answer is given by the expression \((0.75)^4 \times 0.25\), which matches option (d).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
In the world of probability theory, the binomial distribution is a discrete probability distribution. This means it deals with separate or distinct outcomes. It describes the number of successes in a fixed number of trials in an experiment, where each trial has the same probability of success.

Think of it like flipping a coin. Each time you flip the coin is a trial. If you're counting heads, every time you get a head, it's considered a success.
For example, if you flip a coin 10 times, you might want to know the probability of getting exactly 4 heads. In these situations, the binomial distribution is your go-to tool.

Some key aspects of the binomial distribution are:
  • Fixed number of trials: The process is repeated a certain number of times.
  • Two possible outcomes: Each trial can be a success or failure.
  • Constant probability: The probability of success remains the same for every trial.
This probability model is quite powerful, as it helps us understand events like the ones in the fast-food promotion game. However, it's not exactly what Jeff is dealing with here. That's where the geometric distribution comes in.
Geometric Distribution
The geometric distribution is another important concept in probability theory. Unlike the binomial distribution, which counts successes in a fixed number of trials, the geometric distribution models the number of trials needed to achieve the first success.

In the scenario with Jeff and his game pieces, the geometric distribution is the right model to use. Jeff wants to know how many attempts will pass before he wins. He'll keep playing until his first win occurs.

Here are some features of the geometric distribution:
  • It measures the number of trials up to and including the first success.
  • Each trial has two outcomes, often labeled as success or failure.
  • The probability of success remains constant across trials.
Using the geometric distribution, we calculate the probability that Jeff wins on his fifth trial. First, he needs to lose in the first four attempts, with a probability of 0.75 each time, and then win on the fifth attempt, with a probability of 0.25. We multiply these probabilities to find the overall chance of this happening, which is \((0.75)^4 \times 0.25\).
Random Variables
Random variables are fundamental in probability theory and statistics. A random variable is a numerical outcome of a random phenomenon. It converts outcomes of random events into numerical values, which makes complex problems easier to manage.

For example, in Jeff's winning game pieces, the random variable could represent the number of attempts it takes to win. By treating it as a random variable, we can use probability models to find meaningful insights about the outcomes.

Here are some important points about random variables:
  • Random variables can be discrete or continuous, but in Jeff's case, we focus on discrete random variables.
  • They help quantify the outcomes of random processes.
  • With a defined probability distribution, random variables allow us to calculate probabilities of various outcomes.
Understanding random variables is crucial for solving problems where uncertain events must be analyzed or predicted. In our example, using the random variable representing the number of trials until a win, we employ the geometric distribution to derive meaningful probabilities.

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Most popular questions from this chapter

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