/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 102 A fastfood restaurant runs a pro... [FREE SOLUTION] | 91Ó°ÊÓ

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A fastfood restaurant runs a promotion in which certain food items come with game pieces. According to the restaurant, 1 in 4 game pieces is a winner. 102\. If Jeff gets 4 game pieces, what is the probability that he wins exactly 1 prize? (a) 0.25 (b) 1.00 (c) \(\left(\begin{array}{l}4 \\ 1\end{array}\right)(0.25)^{1}(0.75)^{3}\) (d) \(\left(\begin{array}{l}4 \\ 1\end{array}\right)(0.25)^{3}(0.75)^{1}\) (e) \((0.75)^{3}(0.25)^{1}\)

Short Answer

Expert verified
Option (c) is correct: \(\left(\begin{array}{l}4 \\ 1\end{array}\right)(0.25)^{1}(0.75)^{3}\).

Step by step solution

01

Understand the Problem

Jeff receives 4 game pieces in total. The goal is to determine the probability of winning exactly 1 prize. According to the problem, 1 in 4 pieces is a winner, which suggests a probability of winning a single piece as 0.25 (or 25%).
02

Identify the Probability Distribution

The problem statement describes a scenario where each game piece is either a winner or not, which implies a binomial distribution because each piece can independently be a winner with a success probability of 0.25. In a binomial distribution \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \(n\) is the total number of trials (4), \(k\) is the number of successful trials (1 prize), and \(p\) is the probability of success (0.25).
03

Calculate the Probability

Now, plug in the values into the binomial probability formula: \( \binom{4}{1} \times (0.25)^1 \times (0.75)^3 \). First, calculate the binomial coefficient: \( \binom{4}{1} = 4 \). Then perform the remaining calculations: \( (0.25)^1 = 0.25 \) and \( (0.75)^3 = 0.421875 \). Multiply these values together: \( 4 \times 0.25 \times 0.421875 = 0.421875 \).
04

Verify the Solutions

Compare the calculated probability with the given options: \( (c) \ \left(\begin{array}{l}4 \ 1\end{array}\right)(0.25)^{1}(0.75)^{3} \) translates to the same computation, confirming that option (c) is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation involves determining the likelihood of different outcomes. In Jeff's case, where he obtained 4 game pieces, we want to find the probability of winning exactly 1 prize. Probability is a way to quantify uncertainty, expressed as a number between 0 and 1, where 0 means an event will never happen, and 1 means it will always happen.
When dealing with multiple independent events, such as game pieces, we often use specific mathematical formulas to calculate probabilities. Each piece can be either a winner or not. This situation is ideal for binomial probability, which describes the number of successes in a fixed number of independent trials.
The formula used is:
  • \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \)
where \( n \) is the number of trials, \( k \) is the number of successes, \( p \) is the probability of success, and \( (1-p) \) is the probability of failure. This can simplify probability calculations for scenarios like Jeff's game pieces, where each piece's outcome doesn't affect the others.
Statistical Methods
Statistical methods play a pivotal role in analyzing data and making informed decisions. In the context of Jeff's promotion game scenario, statistical methods help us model the chance of winning any given prize. The binomial distribution is a statistical model used to represent situations with a fixed number of independent trials and where each trial has two possible outcomes.
Understanding statistical methods can help in decision-making, prediction, and understanding the variability and uncertainty within a dataset. Here, we use a statistical approach to compute the probability that Jeff wins exactly 1 prize of the 4 game pieces. We employ formulas and coefficients that have been derived to simplify such calculations.
The statistical method relies on choosing the right model, in this case, the binomial distribution, which accurately reflects the scenario. It's crucial to interpret the results, ensuring they align with expected outcomes based on the problem's specifics. Applying statistical methods effectively allows us to not only solve the problem but also gain deeper insights into the nature of the situation being analyzed.
Binomial Coefficient
The binomial coefficient is a central part of binomial probability calculations. It determines the number of ways to choose a subset of items from a larger set, which is crucial for problems like Jeff's where he selects a certain number of winning pieces.
The binomial coefficient \( \binom{n}{k} \) is read as "n choose k" and is calculated using the formula:
  • \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
Here, \( n! \) denotes the factorial of \( n \), which means multiplying together all positive integers up to \( n \). Similarly, \( k! \) and \( (n-k)! \) are factorials of \( k \) and \( (n-k) \) respectively.
In the exercise, \( \binom{4}{1} = 4 \) because there are 4 game pieces and Jeff tries to win 1. This value indicates that there are 4 potential successful arrangements of getting the desired outcome, which is crucial for computing the overall probability in such scenarios.

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Most popular questions from this chapter

"Large Counts condition To use a Normal distribution to approximate binomial probabilities, why do we require that both \(n p\) and \(n(1-p)\) be at least \(10 ?\)

A fastfood restaurant runs a promotion in which certain food items come with game pieces. According to the restaurant, 1 in 4 game pieces is a winner. 103\. If Jeff keeps playing until he wins a prize, what is the probability that he has to play the game exactly 5 times? (a) \((0.25)^{5}\) (b) \((0.75)^{4}\) (c) \((0.75)^{5}\) (d) \((0.75)^{4}(0.25)\) (e) \(\left(\begin{array}{l}5 \\ 1\end{array}\right)(0.75)^{4}(0.25)\)

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