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Prayer and pregnancy Two hundred women who were about to undergo IVF served as subjects in an experiment. Each subject was randomly assigned to either a treatment group or a control group. Women in the treatment group were intentionally prayed for by several people (called intercessors) who did not know them, a process known as intercessory prayer. The praying continued for three weeks following IVF. The intercessors did not pray for the women in the control group. Here are the results: 44 of the 88 women in the treatment group got pregnant, compared to 21 out of 81 in the control group. \({ }^{17}\) Is the pregnancy rate significantly higher for women who received intercessory prayer? To find out, researchers perform a test of \(H_{0}: p_{1}=p_{2}\) versus \(H_{a}: p_{1}>p_{2},\) where \(p_{1}\) and \(p_{2}\) are the actual pregnancy rates for women like those in the study who do and don't receive intercessory prayer, respectively. (a) Name the appropriate test and check that the conditions for carrying out this test are met. (b) The appropriate test from part (a) yields a \(P\) -value of 0.0007 . Interpret this \(P\) -value in context. (c) What conclusion should researchers draw at the \(\alpha=\) 0.05 significance level? Explain. (d) The women in the study did not know whether they were being prayed for. Explain why this is important.

Short Answer

Expert verified
The test is a two-sample z-test for proportions. The P-value indicates a significant difference, leading to rejection of the null hypothesis at \( \alpha = 0.05 \). Blinding prevents bias.

Step by step solution

01

Identify the Appropriate Test

The appropriate test for comparing two proportions is the two-sample z-test for proportions because we are comparing the pregnancy rates between two independent groups (treatment and control).
02

Check Test Conditions

To use the two-sample z-test, we need to check if: (1) We have two independent random samples from large populations, which is valid as stated in the experimental setup. (2) The sampling distribution for the difference in sample proportions is approximately normal. This is supported if both groups meet the conditions: \( n_1 \hat{p}_1 \geq 10, \; n_1 (1-\hat{p}_1) \geq 10, \; n_2 \hat{p}_2 \geq 10, \; n_2 (1-\hat{p}_2) \geq 10 \), where \( n_1 = 88, \; \hat{p}_1 = \frac{44}{88}, \; n_2 = 81, \; \hat{p}_2 = \frac{21}{81} \). Both conditions are satisfied.
03

Interpret the P-value

A \( P \)-value of 0.0007 means that if the null hypothesis \( H_0: p_1 = p_2 \) is true (no difference in pregnancy rates), the probability of observing such a difference in pregnancy rates (or more extreme) by random chance is 0.07%.
04

Draw Conclusion Using α Level

With \( \alpha = 0.05 \), the \( P \)-value of 0.0007 is less than 0.05, meaning we reject the null hypothesis. Researchers conclude that there is a statistically significant difference in pregnancy rates, with the treatment group having a higher rate.
05

The Importance of Blinding

Blinding is important to prevent bias; if participants know they are being prayed for, psychological effects could potentially influence outcomes. The lack of awareness in both groups ensures that any observed effect on pregnancy can be attributed to the intercessory prayer itself, not psychological influence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intercessory Prayer
Intercessory prayer is a type of prayer where individuals, known as intercessors, pray on behalf of others. In the context of this experiment, intercessors prayed for the women who were undergoing IVF treatments. These prayers were conducted without the women knowing who was praying for them or even if they were being prayed for at all.
This kind of setup is designed to remove any potential bias or influence that may come from the woman's knowledge of being prayed for. By ensuring the subjects are unaware of the intercessory prayer, the researchers aim to isolate the effect of the prayer from psychological or placebo effects. This helps ensure that any changes in the outcome can be confidently attributed to the intercessory prayer itself.
Pregnancy Rates
Pregnancy rates in this study refer to the proportion of women who became pregnant in each group: those who received intercessory prayer (treatment group) and those who did not (control group). In statistical terms, a comparison of these rates helps determine if there is a significant difference in outcomes between the groups.
The treatment group had 44 out of 88 women becoming pregnant, yielding a pregnancy rate of \( \hat{p}_1 = \frac{44}{88} \approx 0.5 \) or 50%.
The control group had 21 out of 81 women become pregnant, resulting in a rate of \( \hat{p}_2 = \frac{21}{81} \approx 0.259 \) or 25.9%.
The noticeable difference in these rates forms the basis for performing a statistical test to assess if intercessory prayer significantly impacts pregnancy outcomes.
Significance Level
The significance level, often denoted by \( \alpha \), is a threshold used to decide whether to accept or reject the null hypothesis in statistical tests. In this study, researchers set the significance level at 0.05 (or 5%), meaning they are willing to accept a 5% chance of incorrectly rejecting the null hypothesis (Type I error).
When conducting a statistical test like the two-sample z-test for proportions, the computed \( P \)-value is compared to the significance level. Here, the \( P \)-value of 0.0007 was much lower than the 0.05 threshold. This indicates that there is strong evidence against the null hypothesis, supporting the conclusion that intercessory prayer has a significant effect on increasing pregnancy rates.
Random Assignment
Random assignment is a fundamental process in experimental design, ensuring that each participant has an equal chance of being placed in any of the study groups. In this experiment, women were randomly assigned to either the treatment group or the control group.
The purpose of random assignment is to create comparable groups and control for confounding variables, ensuring that any differences in outcomes can be more confidently attributed to the treatment itself, rather than other extraneous factors.
By randomly assigning women to each group, the researchers aimed to eliminate bias and equalize the distribution of other variables (e.g., age, health conditions) across both the treatment and control groups. This strengthens the validity of the causal conclusions drawn from the experiment.

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Most popular questions from this chapter

Exercises 58 to 60 refer to the following setting. A study of road rage asked random samples of \(596 \mathrm{men}\) and 523 women about their behavior while driving. Based on their answers, each person was assigned a road rage score on a scale of 0 to \(20 .\) The participants were chosen by random digit dialing of phone numbers. The researchers performed a test of the following hypotheses: \(H_{0}: \mu_{M}=\mu_{F}\) versus \(H_{a^{*}} \mu_{M} \neq \mu_{F}\) The \(P\) -value for the stated hypotheses is 0.002 . Interpret this value in the context of this study. (a) Assuming that the true mean road rage score is the same for males and females, there is a 0.002 probability of getting a difference in sample means. (b) Assuming that the true mean road rage score is the same for males and females, there is a 0.002 probability of getting an observed difference at least as extreme as the observed difference. (c) Assuming that the true mean road rage score is different for males and females, there is a 0.002 probability of getting an observed difference at least as extreme as the observed difference. (d) Assuming that the true mean road rage score is the same for males and females, there is a 0.002 probability that the null hypothesis is true. (e) Assuming that the true mean road rage score is the same for males and females, there is a 0.002 probability that the alternative hypothesis is true.

The researchers report that the results were statistically significant at the \(1 \%\) level. Which of the following is the most appropriate conclusion? (a) Because the \(P\) -value is less than \(1 \%\), fail to reject \(H_{0}\). There is not convincing evidence that the proportion of male college students in the study who worked for pay last summer is different from the proportion of female college students in the study who worked for pay last summer. (b) Because the \(P\) -value is less than \(1 \%\), fail to reject \(H_{0}\). There is not convincing evidence that the proportion of all male college students who worked for pay last summer is different from the proportion of all female college students who worked for pay last summer.

Young adults living at home A surprising number of young adults (ages 19 to 25 ) still live in their parents' homes. A random sample by the National Institutes of Health included 2253 men and 2629 women in this age group. \({ }^{11}\) The survey found that 986 of the men and 923 of the women lived with their parents. (a) Construct and interpret a \(99 \%\) confidence interval for the difference in the true proportions of men and women aged 19 to 25 who live in their parents' homes. (b) Does your interval from part (a) give convincing evidence of a difference between the population proportions? Explain.

Paired or unpaired? In each of the following settings, decide whether you should use paired \(t\) procedures or two-sample \(t\) procedures to perform inference. Explain your choice. \({ }^{40}\) (a) To compare the average weight gain of pigs fed two different rations, nine pairs of pigs were used. The pigs in each pair were littermates. A coin toss was used to decide which pig in each pair got Ration \(\mathrm{A}\) and which got Ration \(\mathrm{B}\). (b) Separate random samples of male and female college professors are taken. We wish to compare the average salaries of male and female teachers. (c) To test the effects of a new fertilizer, 100 plots are treated with the new fertilizer, and 100 plots are treated with another fertilizer. A computer's random number generator is used to determine which plots get which fertilizer.

Who talks more-men or women? Researchers equipped random samples of 56 male and 56 female students from a large university with a small device that secretly records sound for a random 30 seconds during each 12.5 -minute period over two days. Then they counted the number of words spoken by each subject during each recording period and, from this, estimated how many words per day each subject speaks. The female estimates had a mean of 16,177 words per day with a standard deviation of 7520 words per day. For the male estimates, the mean was 16,569 and the standard deviation was \(9108 .\) Do these data provide convincing evidence of a difference in the average number of words spoken in a day by male and female students at this university?

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