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Refer to Exercise 80. Construct and interpret a 95% confidence interval for the population mean M. What additional information does the confidence interval provide?

Short Answer

Expert verified

The 95%confldence interval is (297.46,300.61). It intends that there are 95%chances that the mean amount of bottle fllled is somewhere in the range of 297.46and 300.61ml.

Step by step solution

01

Given information

From Question 80, Bottles of a popular cola are supposed to contain 300milliliters (ml) of cola. Because the filling technology is not entirely precise, there is some fluctuation from bottle to bottle. The distribution of the information, in my experience, is about Normal. An inspector measures the contents of six randomly selected bottles from a single day’s production. The results are299.4297.7301.0298.9300.2297.0.

We need to construct and interpret a 95%confidence interval for the population meanM.

02

Explanation

The dataset is


299.4
297.7
301
298.9
300.2
297

The formula to compute the t-interval is:

CI=x¯±tα/2×sn

The obtained output using Ti-83 plus calculator is:

From the above output, the 95%confidence interval is (297.46,300.61). It intends that there are 95%chances that the mean amount of bottle filled is somewhere in the range of 297.46and 300.61ml. Here, 300 lies in the registered confidence interval. Subsequently, there is sufficient evidence to conclude that the mean amount of cola filled in all bottles isn't unique at about 300ml.

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